I'm not sure, but I believe your answer would be
8/10 = 4/20
Forgive me if I'm wrong, but the others seem to say the same thing that this answer doesn't.
First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.


Then, the radii of gyration for
x = √[I_x/m]
y = [I_y/m]
where m = k(15-4)² = 121k. Then,
x = y = [4880.33k/121k] = 40.33
I hope I was able to help you. Have a good day.
Answer: h = 89
Step-by-step explanation: Hope correct :)
Hope it helps to solve it