How many values of x must be excluded in the expression x-2/(x+9)(x-5)

2 answers:

5 0

We have the expression:( x - 2 ) / ( x + 9 ) ( x - 5 )We have to find how many values of x must be excluded. The rule is : denominator must never equal zero. Anything divided by zero is undefined.x + 9 ≠ 0, x ≠ - 9x - 5 ≠ 0, x ≠ 5.Answer: Two values must be excluded, x = - 9 and x = 5.

jeka57 [31]3 years ago

5 0

Answer: There is one excluded value and the excluded value is negative four.

Step-by-step explanation:

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