Question

Suppose the manager of a restaurant in a commercial building has determined that the proportion of customers who drink tea is 24%. Based on a random sample of 300 customers, what is the standard error for the sampling distribution of the sample proportion of tea drinkers?

Answer 1

Answer:

0.427

Step-by-step explanation:

Standard error for the sampling distribution refers to the standard deviation of the samples taken from a population. The standard error equals the standard deviation divided by the square root of the sample size

The probability of customers who drink tea (p) = 24% = 0.24, the sample size of customers (n) = 300.

Standard error = $\frac{\sigma}{\sqrt{n} }$ where σ is the standard deviation.

$\sigma=\sqrt{np(1-p)}$

Standard error = $\frac{\sigma}{\sqrt{n} }= \frac{\sqrt{np(1-p)} }{\sqrt{n} } =\sqrt{\frac{np(1-p)}{n} } =\sqrt{p(1-p)}=\sqrt{0.24(1-0.24)} =0.427$