-9.1
It all rounds up to the tenth place once you try to round to the hundredth's place
Answer:
B) -125a^11
Step-by-step explanation:
(-5a^2)^3·a^5 = (-5)^3·a^6·a^5
= (-5)^3·a^(2·3)·a^5
= (-5)^3·a^6·a^5
= -125·a^(6+5)
= -125·a^11 . . . . matches choice B
_____
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
Answer: Option 2
Step-by-step explanation:
Answer:
The pairs of integer having two real solution for
are
Step-by-step explanation:
Given
Now we will solve the equation by putting all the 6 pairs so we get the following
for 
for 
for 
for 
for 
for 
The above all are Quadratic equations inn general form 
where we have a,b and c constant values
So for a real Solution we must have
for we have
which is less than 0 ∴ not a real solution.
for we have
which is greater than 0 ∴ a real solution.
for we have
which is greater than 0 ∴ a real solution.
for we have
which is greater than 0 ∴ a real solution.
for we have
which is equal to 0 ∴ a real solution.
for we have
which is less than 0 ∴ not a real solution.
