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3 years ago

Solve for g 6(−2g−1)=−(13g+2) g =

Mathematics

2 answers:

uysha [10]3 years ago

7 0

Answer:

g = 4

Step-by-step explanation:

6(−2g−1)=−(13g+2)

Distribute

-12g -6 = -13g -2

Add 13g to each side

-12g + 13g -6 = -13g+13g -2

-6+g =-2

Add 6 to each side

-6+g+6 = -2+6

g = 4

il63 [147K]3 years ago

5 0

Answer:

g = 4

Step-by-step explanation:

6(-2g - 1) = -(13g + 2)

____________________________________________________________

Distribute,

6(-2g - 1)

-12g - 6

Distribute,

-(13g + 2)

-13g - 2

-12g - 6 = -13g - 2

+13 to both sides,

g - 6 = - 2

Add 6 to both sides,

g = 4

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Let b be a number such that (2b+5)(b-1)=6b. What is the largest possible value of b? Express your answer as a common fraction.

Oksi-84 [34.3K]

Answer:

Foil the expression and solve the derivative with respect to b at f'(x)=0 $2b^2+3b+5=6b\\d/dx(2b^2+9b+5=0)\\4b+9=0\\b=-9/4$

Step-by-step explanation:

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3 years ago

What equation represents a line that is parallel to y=3X +5

Lina20 [59]

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4 years ago

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3 years ago

Read 2 more answers

Can anyone help please?

stepladder [879]

Answer:

h(t) = -16t(t-6)

h(2) = 128

Step-by-step explanation:

h(t) = -16t² + 96t

h(t) = -16t(t-6)

t = 3

h(2) = -16(2)(2 - 6)

h(2) = 128

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3 years ago

Thomas needs to buy a cardboard sheet that will allow him to make his 224 in 3 box. To help construct the box, he decided to cut

Slav-nsk [51]

Answer:

Part 1; The volume of the box Thomas wants to make is 224 = 2·w² + 12·w

Part 2; The zeros for the equation of the function, are w = -14, or w = 8

Part 3

The width of the box is 8 inch

The length of the box, is 14 inches

The height of the box, is given as 2 inches

Part 4

Please find attached the graph of the function

Step-by-step explanation:

Part 1

The volume of the box Thomas wants to make, V = 224 in.³

The dimensions he cuts out from the length and width = 2 in² each

The length of the box = 6 inches + The width of the box

Let l represent the length of the box and let w represent the width of the box, we have;

l = 6 + w

The height of the box, h = The length of the cut out square = 2 inches

The volume of the box, V = Length, l × Width, w × Height, h

∴ V = l × w × h

l = 6 + w, h = 2

∴ V = (6 + w) × w × 2

V = 2·w² + 12·w,

The equation of the volume of the box, V = 2·w² + 12·w, where, V = 224

∴ 224 = 2·w² + 12·w

Part 2

The zeros of the equation for the volume of the box, V = 2·w² + 12·w, where, V = 224 are found as follows;

V = 224 = 2·w² + 12·w

∴ 2·w² + 12·w - 224 = 0

Dividing by 2 gives;

(2·w² + 12·w - 224)/2 = w² + 6·w - 112 = 0

∴ (w + 14) × (w - 8) = 0

The zeros for the equation of the function, are w = -14, or w = 8

Part 3

We reject the value, w = -14, therefore, the width of the box, w = 8 inch

The length of the box, l = 6 + w

∴ l = 6 + 8 = 14

The length of the box, l = 8 inches

The height of the box, h, is given as h = 2 inches

Part 4

The graph of the function created with MS Excel is attached

4 0

3 years ago