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DIA [1.3K]
3 years ago
7

Finley's pumpkin had a mass of 6.56.56, point, 5 kilograms (\text{kg})(kg)left parenthesis, start text, k, g, end text, right pa

renthesis before he carved it. After carving it, the pumpkin had a mass of 3.9\,\text{kg}3.9kg3, point, 9, start text, k, g, end text.
What was the percent decrease in the mass of the pumpkin?
Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

40%

Step-by-step explanation:

Finley's pumpkin had a mass of 6.5 kg before he carved it.

After carving it, the pumpkin had a mass of 3.9 kg.

Now, we are asked to determine the % decrease in the mass of the pumpkin.

Therefore, the % decrease in mass is given by  

\frac{\textrm {Initial Mass - Final Mass}}{\textrm {Initial Mass}} \times 100= \frac{6.5 - 3.9}{6.5} \times 100 = 40%. (Answer)

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GalinKa [24]

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7 0
3 years ago
0<br> x+y- 2x +284 +18120<br> The answer
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8 0
3 years ago
How many multiples of 4 are there in {n; 37&lt; n &lt;1001}?
s2008m [1.1K]
Let's begin by listing the first few multiples of 4:  4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44.  So, between 1 and 37 there are 9 such multiples:  {4, 8, 12, 16, 20, 24, 28, 32, 36}.  Note that 4 divided into 36 is 9.

Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:

<span>How many multiples of 4 are there in {n; 37< n <101}?  We could list and then count them:  {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval.  Try subtracting 40 from 100; we get 60.  Dividing 60 by 4, we get 15, which is 1 less than 16.  So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:

1000
   -40
-------
 960

Dividing this by 4, we get 240.  Adding 1, we get 241.

Finally, subtract 9 from 241:  We get 232.

There are 232 multiples of 4 between 37 and 1001.

Can you think of a more straightforward method of determining this number? </span>

5 0
3 years ago
Factorize completely <br> 81k^2 - m^2
Genrish500 [490]

81k^2 - m^2 factors to

(9k + m)(9k - m)

Prove this by FOILing.

First - 81k^2

Outer - (-9km)

Inner - 9km

Last - (-m^2)

Put it into equation form

81k^2 - 9km + 9km - m^2

And combine terms to get the original equation,

81k^2 - m^2.

⭐ Answered by Hyperrspace (Ace) ⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

7 0
3 years ago
Read 2 more answers
A jar contains 38 red marbles numbered 1 to 38 and 38 blue marbles numbered 1 to 38 a marble is drawn at random from the jar
liq [111]

Answer:

P(Red) = 0.50'

P(Odd) = 0.50\\

Step-by-step explanation:

Given

Red = 38

Blue = 38

Required (Missing part of the question)

(a) The marble is red. (b) The marble is odd-numbered

Solving (a): Probability of Red.

This is calculated as:

P(Red) = \frac{Red}{Total}

P(Red) = \frac{38}{38+38}

P(Red) = \frac{38}{76}

P(Red) = 0.50

Solving (b): Probability of Odd

Since each marble type is numbered 1 to 38, then half of it are odd.

i.e. 19 odd numbered red marbles and 19 odd numbered blue marbles.

So, the probability of odd is:

P(Odd) = \frac{Odd}{Total}

P(Odd) = \frac{19+19}{38+38}

P(Odd) = \frac{38}{76}

P(Odd) = 0.50\\

5 0
3 years ago
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