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Neporo4naja [7]
3 years ago
13

The area of a rectangular soccer field is 5000 yd^2. The length of the field is twice the length. Find the dimensions of the fie

ld.
Mathematics
2 answers:
nignag [31]3 years ago
8 0
Length is l, width is w
lw=5000
l=2w
2w^2=5000
w^2=2500
w=50 yd
l=100 yd
harina [27]3 years ago
4 0
You can divide the field into two squares of area 2500 yd^2. The side of each of those will be √2500 = 50 yd.

The dimensions of the field are 50 yd by 100 yd.
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A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po
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The work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

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The work is defined by:

W=\int dFdx (1)    

The force here will be the product between the volume and the kerosene weighing, so we have :

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Then using (1), we have:

W=\int \pi R^{2}dy*50(8-y)  

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W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)

W=450\pi \int_{0}^{8}dy(8-y)

W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)

W=450\pi(8y|_{0}^{8} -\frac{y^{2}}{2}|_{0}^{8})  

W=450\pi(8*8 -\frac{8^{2}}{2})

W=450\pi(64 -\frac{64}{2})

Therefore, the work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

I hope it helps you!  

6 0
3 years ago
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