Here is a clue about a secret number:

What is the answer <br> 1/3x+y=4 <br> Y=

timofeeve [1]

Answer:

${ \tt{ \frac{1}{3} x + y = 4}} \\ \\ → \: { \tt{y = 4 - \frac{1}{3} x}}$

6 0

3 years ago

Brandon is a high school basketball player. In a particular game, he made some two point shots and some three point shots. Brand

seraphim [82]

The system of equations are x+ y =16 and 2y=x.

<h3>What is Algebra?</h3>

Algebra is the part of mathematics that helps represent problems or situations in the form of mathematical expressions

let the two points shots be x

let the three points shots be y.

According to question,

x+ y =16

and,

2y=x

Learn more about algebra here:

brainly.com/question/953809

#SPJ1

7 0

2 years ago

He ate 0.1 times as much dog food on Wednesday as he ate on Tuesday. If her dog ate 6 cups of dog food on Tuesday, how much did

Sveta_85 [38]

Answer:

6.6 cups of dog food

Step-by-step explanation:

6x0.1=.6

6+.6=6.6

4 0

3 years ago

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Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago

75 cm x 50 cm HELP 61 POINTS

katen-ka-za [31]

3,750 cm its simple math really

3 0

3 years ago

Read 2 more answers