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lara [203]
3 years ago
6

A cylinder has a radius of 12.2 inches and a height of 6.1 inches.

Mathematics
2 answers:
Anna [14]3 years ago
8 0

<span>A cylinder has a radius of 12.2 inches and a height of 6.1 inches. What is the volume of the cylinder to the nearest tenth in³? 

</span><span>C. 2852.3 in³</span>
Sladkaya [172]3 years ago
3 0
The answer would be 2850.9in cubed. Just ask if you nee d a justification. Happy to help! 
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What is the volume of the plastic rocket???
Snezhnost [94]

Answer:

A) 151 in³ or 151 cubic inches

Step-by-step explanation:

Volume of rocket = Volume of Cylinder + Volume of Cone

Step 1

Find the volume of the cylinder

Volume of a cylinder = πr²h

r = Diameter/2

= 5/2 = 2.5 inches

h = 6 inches

Hence,

π × 2.5² × 6

= 117.81 cubic inches

Step 2

Find the volume of the cone

Volume of a cone =1/3 πr²h

h = 11 inches - 6 inches

= 5 inches

r = 2.5 inches

Hence,

1/3 × π × 2.5² × 5

= 32.72 cubic inches

Therefore:

Volume of rocket = Volume of Cylinder + Volume of Cone

= 117.81 cubic inches + 32.72 cubic inches

= 150.53 cubic inches

Approximately to the nearest inch = 151 in³ or 151 cubic inches

Option A is correct

7 0
3 years ago
Please help! files attached.
kotykmax [81]
The first question would be x + (x + 4). This is because Max has $x and Keisha has (x + 4) because she has four MORE THAN Max. I am pretty sure that the second one is A, but I am not positive. The first one is right though. I hope this helps!!!
5 0
3 years ago
What is P(2 or divisor of 9)?<br> please explain!
Dmitrij [34]

The probability that a divisor of 2 or 9 is chosen when the spinner is spun once is 2/3.

<h3>What is the probability?</h3>

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

P(2 or divisor of 9) = section that has a divisor of 2/ total number of sections + section that has a divisor of 2/ total number of sections

1/3 + 1/ 3 = 2/3

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

3 0
2 years ago
Plzzzzzzzzz help meeee
Rashid [163]
Table a is 3 b is 2 and c is 1
7 0
3 years ago
In a large population of college-educated adults, the mean IQ is 118 with a standard deviation of 20. Suppose 200 adults from th
cricket20 [7]

Answer: 0.0793

Step-by-step explanation:

Let the IQ of the educated adults be X then;

Assume X follows a normal distribution with mean 118 and standard deviation of 20.

This is a sampling question with sample size, n =200

To find the probability that the sample mean IQ is greater than 120:

P(X > 120) = 1 - P(X < 120)

Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n

Where;  X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size

Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)

                                 = 1 - P(Z< 1.41)

The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207

Thus; P(X< 120) = 1 - 0.9207

                          = 0.0793

3 0
3 years ago
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