All categories

2 years ago

What is the volume of the plastic rocket???

Mathematics

1 answer:

Snezhnost [94]2 years ago

7 0

Answer:

A) 151 in³ or 151 cubic inches

Step-by-step explanation:

Volume of rocket = Volume of Cylinder + Volume of Cone

Step 1

Find the volume of the cylinder

Volume of a cylinder = πr²h

r = Diameter/2

= 5/2 = 2.5 inches

h = 6 inches

Hence,

π × 2.5² × 6

= 117.81 cubic inches

Step 2

Find the volume of the cone

Volume of a cone =1/3 πr²h

h = 11 inches - 6 inches

= 5 inches

r = 2.5 inches

Hence,

1/3 × π × 2.5² × 5

= 32.72 cubic inches

Therefore:

Volume of rocket = Volume of Cylinder + Volume of Cone

= 117.81 cubic inches + 32.72 cubic inches

= 150.53 cubic inches

Approximately to the nearest inch = 151 in³ or 151 cubic inches

Option A is correct

You might be interested in

50 POINTS IF ANSWERED, BRAINLIEST IF EXPLAINED

puteri [66]

M=change in y/change in x
Finding gradient of the orginal line
=3+1/0-3
=-4/3
Since parallel lines are equal the other line would be -4/3 (gradient)
Sub (-3;2) into y=mx+c
2=-4/3 (-3)+c
2=4+5
2-4=c
-2 = c

Therefore sub all your info and you get y= -4/3x-2

6 0

2 years ago

What is the value of x?

Mazyrski [523]

x/20 = 21/14 (similar proportions)

x/20 = 3/2 (simplify by canceling out a factor of 7)

x = 30

6 0

3 years ago

Read 2 more answers

Six word sentences that equal 16

Rzqust [24]

Eight times two equals sixteen.
two times eight equals sixteen.
four times four equals sixteen.
sixteen times one equals sixteen.
one times sixteen equals sixteen.
eight plus eight equals sixteen

8 0

3 years ago

George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.

worty [1.4K]

The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

Step-by-step explanation:

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

The cost of small box of oranges = x
The cost of large box of oranges = y

The system of equations are framed as :

3x + 14y = 203 ---------(1)

11x + 11y = 220 ---------(2)

To solve these equations for x and y values :

Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

33x + 154y = 2233

- (33x + 33y = 660)

121 y = 1573

⇒ y = 1573 / 121

⇒ y = 13

∴ The cost of large box of oranges is $13.

Substitute y=13 in the eq(1),

⇒ 3x + 14(13) = 203

⇒ 3x + 182 = 203

⇒ 3x = 203 - 182

⇒ 3x = 21

⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

7 0

2 years ago

The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian

Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

$x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }$

Then the area of isosceles right triangle will be: $A=\frac{1}{2} x^2$

Therefore the area is: $A=\frac{169}{4}$

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

$S=\frac{a}{1-r}$

Substitute $a=\frac{169}{4} \ and\ r=\frac{1}{4}$ in above formula.

$S=\frac{\frac{169}{4}}{1-\frac{1}{4}}$

$S=\frac{\frac{169}{4}}{\frac{3}{4}}$

$S=\frac{169}{3}$

Hence, the Sum of the areas of theses triangles is 169/3.

7 0

2 years ago