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BartSMP [9]
3 years ago
10

Someone please help me

Mathematics
1 answer:
OlgaM077 [116]3 years ago
5 0

y = 52

52 +52 = 104

180 - 104 = 76


14x+6 = 76

14x = 70

x = 70/14 = 5


the answer is 5



Please mark brainliest

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A large tank is partially filled with 100 gallons of fluid in which 20 pounds of salt is dissolved. Brine containing 1 2 pound o
sertanlavr [38]

Answer:

Step-by-step explanation:

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R_{out} = \dfrac{4A}{100+(6-4)t}

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\dfrac{dA}{dt}+ \dfrac{2}{50+t}A = 3  \ \ \ ... (1)

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\int_c \dfrac{2}{50 +t}dt = e^{2In |50+t|

\int_c \dfrac{2}{50 +t}dt = (50+t)^2

multiplying above integrating factor fields; we have:

(50 +t)^2 \dfrac{dA}{dt} + 2 (50 + t)A = 3 (50 +t)^2

\dfrac{d}{dt}\bigg [ (50 +t)^2 A \bigg ] = 3 (50 +t)^2

(50 + t)^2 A = (50 + t)^3+c

A = (50 + t) + c(50 + t)²

Using the given conditions:

A(0) = 20

⇒ 20 = 50 + c (50)⁻²

-30 = c(50) ⁻²

c = -30 × 2500

c =  -75000

A = (50+t) - 75000(50 + t)⁻²

The no. of pounds of salt in the tank after 35 minutes is:

A(35) = (50 + 35) - 75000(50 + 35)⁻²

A(35) = 85 - \dfrac{75000}{7225}

A(35) =69.6193 pounds

A(35) \simeq 70 pounds

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