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Answer:
3.30185 σ
8.7636
Step-by-step explanation:
the fromula for 100(1-α)% confidence (two sided) for σ is
√(η-1)*s^2/x^2_α/2,V σ
√(η-1)*s^2/x^2_(1-α/2,V) ∴ (v=n+1)
now data given is n = 12 and s=5.2 mg
for 99% CI ,α=0.05 and (n-1)=9 degree of freedom
from chi- square table x^2_(0.025,9)=19.02 ; x_(0.975,9)=2.7
substitute them in above expression we get
3.30185 σ
8.7636