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kap26 [50]
4 years ago
7

Lawrence drives the same distance monday through Friday commuting to and from work. Last week Lawrence drove 25 miles on the wee

kend for a total of 60 miles for the week. Find the distance Lawrence drives each day commuting to and from work
Mathematics
2 answers:
alexira [117]4 years ago
8 0

Answer:

60 - 25 = 35

35 / 7 = 5

Lawrence drives 5 miles each day commuting to and from work.

tiny-mole [99]4 years ago
4 0

Answer:

7 miles

Step-by-step explanation:

60 - 25 = 35

35 miles in 5 days

35/5 = 7 miles

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ikadub [295]
Hey there!

 9 + 91 = 100

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Hope this helps
Have a great day (:
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Please help. What is the height of the beach umbrella?
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4 years ago
Choose the best selection for the
katrin2010 [14]

Answer:

B. Square

Step-by-step explanation:

Finding the side lengths :

<u>Side 1</u>

⇒ d₁ = √(-4 - 0)² + (8 - 8)²

⇒ d₁ = √16

⇒ d₁ = 4

=============================================================

<u>Side 2</u>

⇒ d₂ = √(-4 + 4)² + (8 - 4)²

⇒ d₂ = √16

⇒ d₂ = 4

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<u>Side 3</u>

⇒ d₃ = √(-4 - 0)² + (4 - 4)²

⇒ d₃ = √16

⇒ d₃ = 4

============================================================

<u>Side 4</u>

⇒ d₄ = √(0 - 0)² + (8 - 4)²

⇒ d₄ = √16

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As all sides of the figure are equal, and it creates 4 right angles, it is a square.

4 0
2 years ago
NEED HELP! WILL MARK BRAINLIEST
ICE Princess25 [194]

Answer:

im pretty sure its 27.

Step-by-step explanation:

if g(x) = 20 then the new problem is 20=x-7

20=x-7 . add 7 to both sides

+7=+7 . +7 cancels out the -7

27=x . <<<answer

6 0
3 years ago
A circle has a radius of 9 inches. The Radius is multiplied by 2/3 to form a second circle. How is the ratio of the areas relate
liraira [26]

Answer:

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{r_{1} }{r_{2}}) ^{2}

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii.

Step-by-step explanation:

Radius of first circle (r_{1}) = 9 inches

Area of first circle = \pi r_{1} ^{2}

Area of first circle = 9 × 9 × π = 81 π

Now, since the radius is multiplied by 2/3 for from a new circle.

∴ Radius of the second circle = 9 \times \frac{2}{3} = 6\ inches

Area of second circle =  \pi r_{2} ^{2}

Area of second circle = 6 × 6 × π = 36 π

Now,

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81\pi }{36\pi }

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{9}{6}) ^{2} = (\frac{r_{1} }{r_{2}}) ^{2}

∵ (r_{1}) = 9 inches and (r_{2}) = 6 inches

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii. i.e., \frac {radius\ of\ first\ circle)^{2} }{(radius\ of\ second\ circle)^{2} } = \frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)}

8 0
3 years ago
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