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matrenka [14]
3 years ago
14

(7×4)×What equals 280. I need help with this kind of math. Trying to help my 10 year old daughter.

Mathematics
2 answers:
Zarrin [17]3 years ago
8 0
For a more easier method;

Calculate: 7x4 = 28

Then just multiply it by 10.

28 x 10 = 280

7 x 4 x 10 = 280.
Blizzard [7]3 years ago
5 0
It's 10.

7*4=28.

280/28 = 10.

Hope this helps.
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Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3√5 , KE = 8, LM:KN = 3:5 Find: KM, LM, KN, Area of KLMN
lora16 [44]
Q1)Find KM
As ME is perpendicular to KN, ∠KEM is a right angle
Therefore ΔKEM is a right angled triangle 
KE is given and and ME is also given, we need to find KM
for this we can use Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides.
KM² = KE² + ME²
KM² = 8² + (3√5)²
       = 64 + 9x5
KM = √109
KM = 10.44

Q2)Find LM
It is said that ratio of LM:KN is 3:5
Therefore if we take the length of one unit as x
length of LM is 3x
and the length of KN is 5x
KN is greater than LM by 2 units 
If we take the figure ∠K and ∠N are equal. 
Since the angles on opposite sides of the bases are equal then this is called an isosceles trapezoid. So if we draw a line from L that cuts KN perpendicularly at D, ΔKEM and ΔLDN are congruent therefore KE = DN
since KN is greater than LM due to KE and DN , the extra 2 units of KN correspond to 16 units 
KN = LM + 2x 
2x = KE + DN
2x = 8+8
x = 8
LM = 3x = 3*8 = 24

Q3)Find KN 
Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have;
same height ME = LD perpendicular distance between the 2 parallel sides 
same right angle when the perpendicular lines cut KN
∠K = ∠N 
when 2 angles and one side of one triangle is equal to two angles and one side on another triangle then the 2 triangles are congruent according to AAS theorem (AAS). Therefore KE = DN 
the distance ED = LM
Therefore KN = KE + ED + DN
 since ED = LM = 24
and KE + DN = 16
KN = 16 + 24 = 40
another way is since KN = 5x and x = 8
KN = 5 * 8 = 40

Q4)Find area KLMN
Area of trapezium can be calculated using the following general equation 
Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)
where perpendicular height - ME
2 parallel sides are KN and LM
substituting values into the general equation
Area = 1/2 * ME * (KN+ LM) 
         = 1/2 * 3√5 * (40 + 24)
         = 1/2 * 3√5 * 64
         = 3 x 2.23 * 32
         = 214.66 units²


8 0
2 years ago
Read 2 more answers
NEED HELP! HOPE THIS IS A BETTER PHOTO
avanturin [10]
You need a picture of the data table...
4 0
3 years ago
320 million written out
miv72 [106K]
320,000,000 I think lol
7 0
3 years ago
Read 2 more answers
Find the value of r so the line passes through each pair of points has the give slopes
Art [367]

Answer:

r=64

Step-by-step explanation:

First, let's start with what we have. If we use y=mx+b here's what we can put in:

y=-4x+b

Then we can use one of the given points to find the y-intercept. Since the only complete one is (12,10), we'll use that.

10=-4(12)+b\\10=-48+b\\58=b

So now we have y=-4x+58.

Now we can use our other point with the missing y-value and solve for y.

r=-4(-2)+58\\r=64

So the missing value is 64.

Hope this helps!

7 0
2 years ago
Picture attached thx
dangina [55]
The answer to the question

3 0
3 years ago
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