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USPshnik [31]
3 years ago
9

Solve 3(x - 2) < 18.

Mathematics
2 answers:
zaharov [31]3 years ago
5 0

Answer:

The first option is correct. {x l x <8}

Step-by-step explanation:

aleksandrvk [35]3 years ago
4 0
I hope this helps you



3 (x-2)÷3 <18÷3


x-2 <6


x-2+2 <6+2


x<8
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What is 75 + 15x ≥ 140
melomori [17]
75+ 15x ≥ 140
⇒ 15x ≥ 140-75
⇒ 15x ≥ 65
⇒ x ≥ 65/15
⇒ x ≥ 13/3
⇒ x ≥ 4 1/3

Final answer: x ≥ 4 1/3~
8 0
3 years ago
Which expression is not a polynomial?<br> x³<br> x² - 2x<br> x³ +1<br> 12x
zaharov [31]

Answer:

12x

Step-by-step explanation:

It has no exponent so it is not a polynomial

3 0
2 years ago
What is this? I need help because I’m very bad at linear functions as you can see
Mademuasel [1]
N has to be negative.
5 0
3 years ago
Read 2 more answers
Ten less than 3 times a number is the same as the number plus 4. What is the number?
lys-0071 [83]

Answer:

3x-10=x+4

Step-by-step explanation:

6 0
3 years ago
If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
3 years ago
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