Answer:
Step-by-step explanation:
Let A1 be the area of one square and A2 be the area of second square
So,
A1 = s^2
where s is side of square
So side of one square is 
To calculate the length of fence we need to find the perimeter of the square
So,
P1 = 4 * s
For second square:
The perimeter will be:
So the total fence will be: P1+P2
Answer:
(0, 6)
Step-by-step explanation:
Point T has a coordinate pair of (3, 4). That is, at point T, x = 3, while y = 4.
3 points to the left of T would be a movement on the x-axis. This movement is a run across the x-axis. At T, x = 3. Therefore, 3 points to the left would be a decrease by 3 = 3 - 3 = 0.
3 points to the left of T would leave us with an x coordinate of 0.
2 points above T suggest a rise, which is on the y-axis.
Therefore, at T, y = 4. 2 points above 4 = 4 + 2 = 6. y coordinate would now be 6.
In conclusion, the ordered pair representing 3 points to the left, and 2 points above point T is (0, 6).
B=kt
constant is k
b=0.25t
constant of proprtionality is 0.25
