Answer:
Option B
Step-by-step explanation:
Looking at the options, option B is correct because when multiplying it by matrix A, it yields the matrix AB as follows;
First row of A multiplied by first column of matrix in option D;
(1 × -1) + (0 × 0) + (0 × 0) = -1 which corresponds to the first number on the first row of Matrix AB
Since majority of matrix AB are zero, I will just prove the ones that are not zero.
Thus;
Second row of matrix A is multiplied by second column of matrix in option D;
(0 × 0) + (-1 × -1) + (0 × 0) = 1 which is same as 2nd number on second row in matrix AB
Lastly, third row of matrix A is multiplied by third column of matrix in option D;
(0 × 0) + (0 × 0) + (1 × -1) = -1 which is same as third number in third row in matrix AB
Answer:
Part a)
Steve's expression is 
For x=3, the expression is equal to 
Part b)
Jasmine's expression is
For x=2, the expression is equal to 
Step-by-step explanation:
Part a)
Let
n-----> the first term
The expression is
substitute
Steve's expression is
Evaluate for x=3
Part b)
Let
n-----> the first term
Jasmine's expression is
Evaluate for x=2
AnswerASK THE TEACHER
Step-by-step explanation:
60 mins in an hour
18/60 is the fraction
3/10 is the simplest form (dividing by 6)
12 ^3 and 11^3 haven't got the same base so the rules of exponents do not apply.
Bases have to be the same:- for example 12^3 * 12*3 = 12 ^(3+3) = 12^6
