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uranmaximum [27]
3 years ago
7

-1 ≤ n+2 ≤ 6

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0
-1 ≤ n + 2 ≤ 6
-2         - 2  + -3
-3      n/    0 

                 Answer = -3 , 4            Answer = C 
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How to solve 2x^2 - 4x = 3
zhenek [66]

Answer:

1 ± i(1/2)√2

Step-by-step explanation:

Write this quadratic in standard form:  subtract 3 from both sides.  This results in 2x^2 - 4x - 3 = 0.  Let's apply the quadratic formula.  The coefficients of the x terms are 2, -4 and -3, so the discriminant is (-4)^2 - 4(2)(-3), or 16 - 24 = -8.

Following the format of the quadratic formula, we get

     -(-4) ±i2√8       4 ±i2√2        

x = ----------------- = --------------- =  1 ± i(1/2)√2

               4                    4

6 0
2 years ago
Solve the following problem.
Elza [17]

Answer:

X = 30

Step-by-step explanation:

20^2 + 23^2 = x^2

400 + 529 = x^2

929 = x^2

√929 = √x^2

X = √929

X = 30.48

5 0
2 years ago
Read 2 more answers
Need help please!!!!!!!!!!
jeka94

1) To create an equation with r isolated, you divide both sides by π and square root both (it is given that all variables are positive). The equation is √A/π = r.

2) Plugging in the numbers give us <em>√54/(22/7) = r</em>.

√54(22/7) can be rewritten as √54*7/22, which is √378/22, which can be simplified to √189/11, or about 17.18.

5 0
3 years ago
A test consists of six
Brums [2.3K]
True/false questions grant a 50% chance for each question. If there are 6 questions, the probability of getting 3 right is 50%. You can find the answer by multiplying the percentages for each outcome.

50% × 50% = 25%

The student ultimately has a 25% chance of getting 3 of the 6 true/false questions correct.
5 0
2 years ago
In the form of the matrice, how do you work out the following simultaneous equation?
lapo4ka [179]
\left[\begin{array}{ccc}1&3&7\\1&1&1\end{array}\right]
multiply 2nd row by -1 and add to first row
\left[\begin{array}{ccc}0&2&6\\1&1&1\end{array}\right]
divide the 1st row by 2
\left[\begin{array}{ccc}0&1&3\\1&1&1\end{array}\right]
multiply the first row by -1 and add to 2nd row
\left[\begin{array}{ccc}0&1&3\\1&0&-2\end{array}\right]

now we know
y+3=0
x-2=0

therefor
y=-3
x=2
4 0
2 years ago
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