Answer:
The sum of the digit of the product is 13
Step-by-step explanation:
Given

Solving (a): The product


Solving (b): The sum of the digits


Answer:
The graph has a removable discontinuity at x=-2.5 and asymptoe at x=2, and passes through (6,-3)
Step-by-step explanation:
A rational equation is a equation where

where both are polynomials and q(x) can't equal zero.
1. Discovering asymptotes. We need a asymptote at x=2 so we need a binomial factor of

in our denomiator.
So right now we have

2. Removable discontinues. This occurs when we have have the same binomial factor in both the numerator and denomiator.
We can model -2.5 as

So we have as of right now.

Now let see if this passes throught point (6,-3).


So this doesn't pass through -3 so we need another term in the numerator that will make 6,-3 apart of this graph.
If we have a variable r, in the numerator that will make this applicable, we would get

Plug in 6 for the x values.



So our rational equation will be

or

We can prove this by graphing
Answer:
a: 4
b: package and shopping costs
c: 1/2 ( (6-3)/(16-10) )
d: cost of shipping per pound
e: y= 1/2x + 4
f: 92
Step-by-step explanation:
Okay bunch of answers
Answer:
x=0.996
Step-by-step explanation:

To take natural log ln , we need to get e^2x alone
Subtract 5 on both sides

Now we divide both sides by 3

Now we take 'ln' on both sides

As per log property we can move exponent 2x before ln

The value of ln(e) = 1

Divide both sides by 2

x= 0.996215082
Round to nearest thousandth
x=0.996
Answer:9787987987987987899999999888888888888888888'
Step-by-step explanation:
that that that 14523095480239845023984203984230482309423094823029834