Answer:
Option G
Step-by-step explanation:
We know that both triangles are similar in proportion. We see that the base of 8 is similar to 6, and therefore the side length of x should be similar to 5.
x/5 = 8/6
Cross multiply.
6x = 40
x = 40/6
x = 6 + 2/3
x = 6.67
R + b = 21
2b = r
now we sub eq 2 into eq 1
r + b = 21
2b + b = 21
3b = 21
b = 21/3
b = 7
2b = r
2(7) = r
14 = r
so there are 7 bluejays (b) and 14 robins (r)...for a total of 21
Answer:
it can be a pain when nobody helps... ur top right is correct
Step-by-step explanation:
heres a screenshot ..
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
