Answer:
2.5% and 2.5 · 10^-3, 0.25, 2/5, √5
Step-by-step explanation:
0.25, 2/5, 2.5 · 10^-3, 2.5%, √5
Now let's list them all in the same form, why not decimals.
0.25 = 0.25
2/5 = 4/10 = 40/100 = 0.4
2.5 · 10^-3 = 2.5 · 0.01 = 0.025
2.5% = 0.025
√5 ≅ 2.236
A]
D=R×t
d=5.8r
d2=5.1(r+7)
0.7r=35.7
r=51 mi/hr
thus the average speed on the outbound trip would be:
51+7=58 mi/hr
b]
let speed of fishing boat=x km/h
speed of cruise ship=(x+12.5) km/h
distance traveled by fishing boat=11.5×x=11.5x km
distance traveled by cruise ship=(x+12.5)×11=(11x+137.5) km
Total distance covered by the ships:
11.5x+11x+137.5=322
22.5x=322-137.5
22.5x=184.5
thus
x=184.5/22.5
x=8.2 km/h
The speed of fishing boat is 8.2 km/hr
Maximum because it contains quartile one 3 and the media
Answer:
466
Step-by-step explanation:
50 + 8*52 = 466
