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2 years ago

1

Mathematics

2 answers:

Mademuasel [1]2 years ago

5 0

Yes should be the right answer

Vlad [161]2 years ago

3 0

Answer:

Yes

Step-by-step explanation:

The pythagorean theroem is: A^2 + B^2 = C^2

I tried this and it works so yes, the right traingle can be made.

The 2 legs are, 64 and 36, while the hyptenouse is 100.

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NeTakaya

Answer:

The Answer would be No

Step-by-step explanation:

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2 years ago

What is the y intercept of the line y = 2x+1?

Tresset [83]

Answer:

Step-by-step explanation:

the equation for a slope-intercept line is y=mx+b. In this equation, b represents the y intercept. In the equation you posted, 1 is in the place of b, so one is the y intercept.

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2 years ago

Read 2 more answers

The director of a marching band asks the band members to line up in rows of four, but one is left over. Then she tries to line t

lions [1.4K]

I got 81 members. 4 x 20 = 80 81-80=1
6 x 13= 78 81-78= 3
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2 years ago

The model represents an equation. What value of x makes the equation true?

Anuta_ua [19.1K]

Answer:

I think i wanna say one of the fractions

Step-by-step explanation:

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2 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

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2 years ago