A ladder is placed in such a way that it reaches a window 12 m high from the ground on placing it against a wall at a distance x
2 answers:
Answer:
9 m
Step-by-step explanation:
Suppose AB is the ladder. AC is the height of the window above the ground and BC is the distance of the foot of ladder from the wall.
The triangle ABC is right angled at C.
∴ AB² = AC² + BC²
=> 15² = 12² + x²
=> 225 - 144= x²
=> 81 = x²
=> 9 = x
- Hence, distance of the foot of the ladder from the wall is 9 m.
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Complete question is attached.
Answer:
B) 8
Step-by-step explanation:
In this question, KLMN ~ PQRS. This means they are similar shapes.
From the image, we could denote that:
KL ~ PQ
LM ~ QR
Given that:
KL = 12
PQ = 30
QR = 20
LM = x
To find x, let's use tge expression:
Cross multiplying, we have:
12 * 20 = 30x
240 = 30x
To find x, let's divide both sides by 30.
8 = x
x = 8
The correct option is option B.
