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3 years ago

Manuel's division is shown.

Mathematics

2 answers:

Margaret [11]3 years ago

7 0

24 /a+3is the answer..................
HOPE IT HELPS YOU '_'

Marrrta [24]3 years ago

4 0

Answer:

$\frac{24}{a+3}$

Step-by-step explanation:

$Dividend = a^{2} -4a+3$

$Divisor =a+3$

Using long division method.

Dividend= (Divisor * Quotient)+Remainder

$a^{2} -4a+3=([a+3]*a)+(-7a+3)$

$a^{2} -4a+3=([a+3]*[a-7])+(24)$

Thus the remainder is 24

Since Manuel left the calculation : -7a+3-(-7a-21)= -7a+3+7a+21= 24

Solving his left calculation further we get the remainder 24.

Hence the remainder over divisor is $\frac{24}{a+3}$

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2 years ago

What is the value of x in the diagram below?

Furkat [3]

Hi,
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3 years ago

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An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is 0.5 s and 7 s.

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

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Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$

Therefore, the debris will reach a height of 56 ft twice.

When time $t=0.5\ s$ during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at $t=7\ s$ , the height is 56 ft.

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