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3 years ago

Manuel's division is shown.

Mathematics

2 answers:

Margaret [11]3 years ago

7 0

24 /a+3is the answer..................
HOPE IT HELPS YOU '_'

Marrrta [24]3 years ago

4 0

Answer:

$\frac{24}{a+3}$

Step-by-step explanation:

$Dividend = a^{2} -4a+3$

$Divisor =a+3$

Using long division method.

Dividend= (Divisor * Quotient)+Remainder

$a^{2} -4a+3=([a+3]*a)+(-7a+3)$

$a^{2} -4a+3=([a+3]*[a-7])+(24)$

Thus the remainder is 24

Since Manuel left the calculation : -7a+3-(-7a-21)= -7a+3+7a+21= 24

Solving his left calculation further we get the remainder 24.

Hence the remainder over divisor is $\frac{24}{a+3}$

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Solve the following system. y = x 2 - 9x + 10 and x + y + 5 = 0. Enter the solution with the smaller x value first.

pochemuha

X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)

7 0

3 years ago

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Louis was served 145 g of meat

tamaranim1 [39]

What is the rest of the question

5 0

3 years ago

Company A: $39.99 per month no installation fee

Svetlanka [38]

Company A represents a proportional relationship, while company B does not.

<h3>Proportional relationship</h3>

The general format of a equation representing a proportional relationship is given as follows:

y = rx.

A proportional relationship is a special case of a linear function, having an intercept of zero.

Then, the output variable y is calculated as the multiplication of the input variable x by the constant of proportionality k.

The costs for each company after x months, in this problem, are represented as follows:

A(x) = 39.99x.

B(x) = 34.99x + 50.

Company B has an intercept different of zero, hence it is not a proportional relationship, while Company A, with an intercept of zero, represents a proportional relationship.

<h3>Missing Information</h3>

The complete problem is:

Two companies offer digital cable television as described below.

Company A: $39.99 per month no installation fee

Company B: $34.99 per month with a $50 installation fee

For each company tell whether the relationship is proportional between months of service and total cost is a proportional relationship. Explain why or why not

More can be learned about proportional relationships at brainly.com/question/10424180

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6 0

1 year ago

Represent the given condition using a single variable, x. Three consecutive odd integers.

Iteru [2.4K]

X
X+2
X+4

Those are 3 consecutive odd integers

8 0

3 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

4 0

3 years ago