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Alex787 [66]
3 years ago
13

A piece of copper with a volume of 8.25 cm³ has a mass of 73.92 g. A piece of iron with a volume of 5 cm³ and has a mass of 39.3

5 g. Which metal has the greater density?
Mathematics
1 answer:
skad [1K]3 years ago
4 0
Density<span> = Mass ÷ Volume

</span>
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Which compound inequalities have the solution set represented by the given graph? Check all that apply
Contact [7]

We check with each options

'Or' represents the intersection of two graphs

'And' represents two separate graphs'

We have two separate shaded part in the given graph

So we ignore the options that has 'and' in between

LEts check first  and second option

\frac{x}{2}=13

Simplify the first part and second part

multiply both sides by 2 .

x < 2  or  4x - 2 > = 26

solve 4x-2 > = 26

add 2 on both sides and then divide both sides by 4

4x >= 28

x >= 7

So solution is x<2 or x>=7 . that is the graph on number line

Lets check with second option

3x-3<3  or  2x+8>=22

add 3 on both sides

3x < 6

divide both sides by 3

so x< 2

2x+8>=22

subtract 8 on both sides

2x >= 30

divide both sides by 2

x >= 15

x<2  or x>=15 that does not satisfies the graph

So option A is correct



7 0
3 years ago
Read 2 more answers
Which data collections show bias? Check all that apply
Natalija [7]

Answer:

Those answers are correct that are shown and that are shown in blue

Step-by-step explanation:

8 0
3 years ago
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5x + 10/ x+2 *2x/4x-10
Margarita [4]

I believe this would be 5x/2x-5

Hope this helps!

3 0
3 years ago
An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a
MAVERICK [17]

Answer:

Probability Mass Function:

   x:          0                         1                            2                          3

P(x):          0.000064          0.004608             0.115902             0.884736

Step-by-step explanation:

We are given the following information:

We treat correct classification  as a success.

P(correct classification) = 0.96

Then the number of classification follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3 and x = 0, 1, 2, 3

We have to evaluate:

P(x = 0)\\= \binom{3}{0}(0.96)^0(1-0.96)^3\\=0.000064

P(x = 1)\\= \binom{3}{1}(0.96)^1(1-0.96)^2\\=0.004608

P(x = 2)\\= \binom{3}{2}(0.96)^2(1-0.96)^1\\=0.115902

P(x = 3)\\= \binom{3}{3}(0.96)^3(1-0.96)^0\\=0.884736

PMF:

   x:          0                         1                            2                          3

P(x):          0.000064          0.004608             0.115902             0.884736

8 0
3 years ago
Select all the expressions that are equivalent to 12b-18
mylen [45]
Answers will be A and B
6 0
3 years ago
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