Question

In 2018 the state of Arizona has a population of 7,123,898 this is an increase from 2010 when a population of 6,392,017 if the area of Arizona covers 113,998MI squared then what is the difference in population density between 2010 in 2018

Answer 1

Answer:

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²

Step-by-step explanation:

The population density is the number of habitants divided by the area.

Arizona:

Has an area of 113,998MI².

2010:

6,392,017 habitants, so the density was 6,392,017/113,998 = 56.07 hab/MI².

2018:

7,123,898 habitants, so the density was 7,123,898/113,998 = 62.49 hab/MI²

Difference:

62.49 - 56.07 = 6.42 hab/MI²

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²