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melomori [17]
3 years ago
9

In 2018 the state of Arizona has a population of 7,123,898 this is an increase from 2010 when a population of 6,392,017 if the a

rea of Arizona covers 113,998MI squared then what is the difference in population density between 2010 in 2018
Mathematics
1 answer:
Effectus [21]3 years ago
4 0

Answer:

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²

Step-by-step explanation:

The population density is the number of habitants divided by the area.

Arizona:

Has an area of 113,998MI².

2010:

6,392,017 habitants, so the density was 6,392,017/113,998 = 56.07 hab/MI².

2018:

7,123,898 habitants, so the density was 7,123,898/113,998 = 62.49 hab/MI²

Difference:

62.49 - 56.07 = 6.42 hab/MI²

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²

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