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melomori [17]
3 years ago
9

In 2018 the state of Arizona has a population of 7,123,898 this is an increase from 2010 when a population of 6,392,017 if the a

rea of Arizona covers 113,998MI squared then what is the difference in population density between 2010 in 2018
Mathematics
1 answer:
Effectus [21]3 years ago
4 0

Answer:

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²

Step-by-step explanation:

The population density is the number of habitants divided by the area.

Arizona:

Has an area of 113,998MI².

2010:

6,392,017 habitants, so the density was 6,392,017/113,998 = 56.07 hab/MI².

2018:

7,123,898 habitants, so the density was 7,123,898/113,998 = 62.49 hab/MI²

Difference:

62.49 - 56.07 = 6.42 hab/MI²

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²

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aleksandrvk [35]

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Brent is saving for a computer that is $840. He will also need to pay a 6% sales tax. What is the total cost of the computer aft
Kobotan [32]

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Read 2 more answers
Will give brainliest if right
inn [45]

As the Remainder Theorem points out, if you divide a polynomial p(x) by a factor x – a of that polynomial, then you will get a zero remainder. Let's look again at that Division Algorithm expression of the polynomial:

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p(x) = (x – a)q(x) + r(x)

If x – a is indeed a factor of p(x), then the remainder after division by x – a will be zero. That is:

p(x) = (x – a)q(x)

In terms of the Remainder Theorem, this means that, if x – a is a factor of p(x), then the remainder, when we do synthetic division by

x = a, will be zero.

The point of the Factor Theorem is the reverse of the Remainder Theorem: If you synthetic-divide a polynomial by x = a and get a zero remainder, then, not only is x = a a zero of the polynomial (courtesy of the Remainder Theorem), but x – a is also a factor of the polynomial (courtesy of the Factor Theorem).

Just as with the Remainder Theorem, the point here is not to do the long division of a given polynomial by a given factor. This Theorem isn't repeating what you already know, but is instead trying to make your life simpler. When faced with a Factor Theorem exercise, you will apply synthetic division and then check for a zero remainder.

Use the Factor Theorem to determine whether x – 1 is a factor of

    f (x) = 2x4 + 3x2 – 5x + 7.

For x – 1 to be a factor of  f (x) = 2x4 + 3x2 – 5x + 7, the Factor Theorem says that x = 1 must be a zero of  f (x). To test whether x – 1 is a factor, I will first set x – 1 equal to zero and solve to find the proposed zero, x = 1. Then I will use synthetic division to divide f (x) by x = 1. Since there is no cubed term, I will be careful to remember to insert a "0" into the first line of the synthetic division to represent the omitted power of x in 2x4 + 3x2 – 5x + 7:

completed division: 2  2  5  0  7

Since the remainder is not zero, then the Factor Theorem says that:

x – 1 is not a factor of f (x).

Using the Factor Theorem, verify that x + 4 is a factor of

     f (x) = 5x4 + 16x3 – 15x2 + 8x + 16.

If x + 4 is a factor, then (setting this factor equal to zero and solving) x = –4 is a root. To do the required verification, I need to check that, when I use synthetic division on  f (x), with x = –4, I get a zero remainder:

completed division: 5  –4  1  4  0

The remainder is zero, so the Factor Theorem says that:

x + 4 is a factor of 5x4 + 16x3 – 15x2 + 8x + 16.

In practice, the Factor Theorem is used when factoring polynomials "completely". Rather than trying various factors by using long division, you will use synthetic division and the Factor Theorem. Any time you divide by a number (being a potential root of the polynomial) and get a zero remainder in the synthetic division, this means that the number is indeed a root, and thus "x minus the number" is a factor. Then you will continue the division with the resulting smaller polynomial, continuing until you arrive at a linear factor (so you've found all the factors) or a quadratic (to which you can apply the Quadratic Formula).

Using the fact that –2 and 1/3 are zeroes of  f (x) = 3x4 + 5x3 + x2 + 5x – 2, factor the polynomial completely.   Copyright © Elizabeth Stapel 2002-2011 All Rights Reserved

If x = –2 is a zero, then x + 2 = 0, so x + 2 is a factor. Similarly, if x = 1/3 is a zero, then x – 1/3 = 0, so x – 1/3 is a factor. By giving me two of the zeroes, they have also given me two factors: x + 2 and x – 1/3.

Since I started with a fourth-degree polynomial, then I'll be left with a quadratic once I divide out these two given factors. I can solve that quadratic by using the Quadratic Formula or some other method.

The Factor Theorem says that I don't have to do the long division with the known factors of x + 2 and x – 1/3. Instead, I can use synthetic division with the associated zeroes –2 and 1/3. Here is what I get when I do the first division with x = –2:

completed divison: bottom row:  3  –1  3  –1  0

The remainder is zero, which is expected because they'd told me at the start that –2 was a known zero of the polynomial. Rather than starting over again with the original polynomial, I'll now work on the remaining polynomial factor of 3x3 – x2 + 3x – 1 (from the bottom line of the synthetic division). I will divide this by the other given zero, x = 1/3:

completed division:  bottom row:  3  0  3  0

 

3x2 + 3 = 0

3(x2 + 1) = 0

x2 + 1 = 0

x2 = –1

x = ± i

If the zeroes are x = –i and x = i, then the factors are x – (–i) and x – (i), or x + i and x – i. I need to   divided off a "3" when I solved the quadratic; it is still part of the polynomial, and needs to be included as a factor. Then the fully-factored form is:

3x4 + 5x3 + x2 + 5x – 2 = 3(x + 2)(x – 1/3)(x + i)(x – i)

7 0
3 years ago
A park district has 45 pine trees and 30 oak trees to be planted. They are separating the trees for different areas. They want e
Lady_Fox [76]

Answer:

greatest number of areas that can be created=5

Step-by-step explanation:

given data

Number of pine trees = 45

Number of oak trees = 30

solution

we want area have same number of both trees

so we get here greatest number of area

we find here  greatest common factor of 45 and 30

so Prime factorization of 45 and 30 are

45 = 3 × 3 ×  5

30 = 2 × 3 ×  5

as here GCF = 5

so here greatest number of areas that can be created=5

6 0
2 years ago
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