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melomori [17]
3 years ago
9

In 2018 the state of Arizona has a population of 7,123,898 this is an increase from 2010 when a population of 6,392,017 if the a

rea of Arizona covers 113,998MI squared then what is the difference in population density between 2010 in 2018
Mathematics
1 answer:
Effectus [21]3 years ago
4 0

Answer:

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²

Step-by-step explanation:

The population density is the number of habitants divided by the area.

Arizona:

Has an area of 113,998MI².

2010:

6,392,017 habitants, so the density was 6,392,017/113,998 = 56.07 hab/MI².

2018:

7,123,898 habitants, so the density was 7,123,898/113,998 = 62.49 hab/MI²

Difference:

62.49 - 56.07 = 6.42 hab/MI²

The difference in population density between 2010 and 2018 is of 6.42 hab/MI²

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The area of the circle formula --> \pi r^2

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            <em>Length of radius is half of diameter which is 14km long</em>

<em />

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sasho [114]

Answer:

The distance between the 6th and 10th seat is approximately 126m

Step-by-step explanation:

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The circumference of the circle is 377m

At this point, we will have to take note that the pods are equally spaced.

To get the distance between the sixth pod and the tenth pod, we will have to use the principle of fractions of a whole.

There are 12 seats in total, the distance between the 6th and tenth seat is 4 seats. Expressing this distance in terms of seats, as a fraction is 4/12 equally spaced seats.

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Answer:

-6=7 NO SOLUTION

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