Answer:
The percent of the people who tested positive actually have the disease is 38.64%.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = a person has the disease
<em>P</em> = the test result is positive
<em>N</em> = the test result is negative
Given:
Compute the value of P (P|X) as follows:
Compute the probability of a positive test result as follows:
Compute the probability of a person having the disease given that he/she was tested positive as follows:
The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.
Answer:
In mathematics, a differential equation is an equation that relates one or more functions and their derivatives. In applications, the functions generally represent physical quantities, the derivatives represent their rates of change, and the differential equation defines a relationship between the two.
Step-by-step explanation:
It looks like you have the domain confused for the range! You can think of the domain as the set of all "inputs" for a function (all of the x values which are allowed). In the given function, we have no explicit restrictions on the domain, and no situations like division by 0 or taking the square root of a negative number that would otherwise put limits on it, so our domain would simply be the set of all real numbers, R. Inequality notation doesn't really use ∞, so you could just put an R to represent the set. In set notation, we'd write
and in interval notation,
The <em>range</em>, on the other hand, is the set of all possible <em>outputs</em> of a function - here, it's the set of all values f(x) can be. In the case of quadratic equations (equations with an x² term), there will always be some minimum or maximum value limiting the range. Here, we see on the graph that the maximum value for f(x) is 3. The range of the function then includes all values less than or equal to 3. As in inequality, we can say that
,
in set notation:
(this just means "f(x) is a real number less than or equal to 3")
and in interval notation:
![(-\infty,3]](https://tex.z-dn.net/?f=%20%28-%5Cinfty%2C3%5D%20)
You can write i I as 1/4 of a 3rd
Y = mx + b
First equation 1 = m(4) + b, bring everything to one side m(4) + b - 1 = 0
Second equation 7 = m(5) + b, bring everything to one side m(5) + b - 7 = 0
Set them equal to each other,
m(4) + b - 1 = m(5) + b - 7
If you bring the b over to the left hand side it becomes
m(4) + b - b - 1 = m(5) - 7
m(4) - 1 = m(5) - 7
Solve for m
6 = m
Plug m = 6 into either equation from the beginning,
m(4) + b - 1 = 0
6(4) + b - 1 = 0
24 + b - 1 = 0
b = -23
Knowing m and b we can now make an equation
y = mx + b
y = 6x -23 Final answer
