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andreev551 [17]
3 years ago
9

Rename 7/20 as a percent

Mathematics
1 answer:
igomit [66]3 years ago
7 0

Step-by-Step Explanation:

a) Rename \frac{7}{20} as a percent

\frac{7}{20}\times 100\\\\=7\times 5\\\\=35\%

b) Rename .245 as a percent

.245\times 100\\\\=\frac{245}{1000}\times 100\\\\=24.5\%

c) Rename 28% as a fraction and a decimal in simplest form

28\%=\frac{28}{100}=\frac{7}{4}\text{ as a fraction}\\\\\frac{7}{4}=1.75\text{ as a decimal}

d) Put .367,36.5%, \frac{9}{25} in order least to greatest.

\text{ First we put change all into percent form}\\\\.367\times 100=\frac{367}{1000}\times 100=36.7\%\\\\\frac{9}{25}\times 100=9\times 4=36\%

Now, we have 36.7%, 36.5%, 36%

We have write it in ascending order i.e. least to greatest ,

Here it is,

36%, 36.5%, 36.7%

\frac{9}{25},36.5\%\ and\ .367

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Can you completely over a 4 ft by 8 ft area with 3 ft by 3 ft tiles?
Vika [28.1K]

Yes, but not without cutting some of the tiles into smaller pieces.

The length of the area is 8-ft.  That's (2 and 2/3) tiles long.

The width of the area is 4-ft.  That's (1 and 1/3) tiles wide.

So you can't just put down rows and columns of whole tiles
and cover the whole area.
______________________________________

Another way to look at it:

-- The area of the whole big plot is  (8 x 4) = 32 square feet.

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-- You can't cover 32 square feet with 9-square-feet pieces.
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6 0
3 years ago
3.41 repeating as a simplified fraction
HACTEHA [7]

Answer:

3 37/90

Step-by-step explanation:

You didn't ask for the work. Hope this helps.

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3 years ago
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Taya2010 [7]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Select all of the equations that have the same solution as the equation -9(x-18)=108
guapka [62]
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3 years ago
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A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac
sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

N_{t} = N_{0}e^{-\lambda t}

Where:

N(t): is the amount of the sample at time t =?

N₀: is the initial quantity of the sample = 120 g

t = 40 min

λ: is the decay constant =  0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g

     

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

5 0
3 years ago
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