There are two choices for each child: overweight (o) or underweight (u). So if the first child is o the next can be o or u. If the first is u the second can be o or u. This gives four possibilities. Here the first child is the letter noted first and the second is the one listed second:
OO
OU
UO
UU
There are 4 outcomes and if each is equally likely then the probability of each is 1/4. Thus the probability of UU is 1/4
The probability of one underweight and one over weight is 1/2 because in two of the outcomes listed above there is one O and one U (namely OU and UO). Since there are 4 outcomes the probability is 2/4 = 1/2
The answer is: parent function
2 consecutive even integers : x and x + 2
x + x + 2 = 170
2x + 2 = 170
2x = 170 - 2
2x = 168
x = 168/2
x = 84
x + 2 = 84 + 2 = 86
so ur 2 numbers are 84 and 86
Answer:
HI = 8
TU = 45
Step-by-step explanation:
→ Find the scale factor enlargement
45 ÷ 10 = 4.5
→ Multiply JI by the scale factor to find it
10 × 4.5 = 45
→ Divide UV by the scale factor to find it
36 ÷ 4.5 = 8
Its B.. Hope that helps :)
