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Eddi Din [679]
3 years ago
7

If a standard die is rolled twice, what is the probability that it lands on a

Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

1/9 or 11.11%

Step-by-step explanation:

On a standard die, there are two numbers greater than 4, 5 and 6. 5 and 6 make up 2/6 of a die, or 1/3. So the probability of getting 5 or 6 once is 1/3 then to find the probability of doing it twice in a row, multiply 1/3 by 1/3( its the same number because there is no innate difference in the rolls). 1/3*1/3=1/9.  

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Add or subtract them in simplest form please help me as fast as possible
NARA [144]

Answer:

Okay so im seeing you need help okay I will tell you how to do number 21 as an example

Step-by-step explanation:

Look for a commen donominater of the 3/8 and 1/3 the denominater would be 24 so 8 times 3 and 3 times 3 so those would be 9/24 and 3/24 , do the 8 plus the ten and you get 18 so 18+ 9/24+3/24= 18 12/24, or 18 1/2

8 0
3 years ago
I need help people help me
sineoko [7]

Answer:

87

Step-by-step explanation:

all the angles of a triangle out of 180 so subtract the two numbers you have from 180

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2 years ago
Read 2 more answers
PLSS HELP ME!!!<br><br><br>question <br><br>3x - 4/5= - 1/2<br><br>what is the value of x?​
Minchanka [31]

Answer:

x = \frac{1}{10}

Step-by-step explanation:

Given

3x - \frac{4}{5} = - \frac{1}{2}

Multiply through by 10, the lcm of 5 and 2 to clear the fractions

30x - 8 = - 5 ( add 8 to both sides )

30x = 3 ( divide both sides by 30 )

x = \frac{3}{30} = \frac{1}{10}

7 0
3 years ago
What is the value of a?
Luda [366]

Answer:

a = 62

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

a + 47+71 = 180

Combine like terms

a +118 = 180

Subtract 118 from each side

a+118-118=180-118

a =62

7 0
3 years ago
Hello again! This is another Calculus question to be explained.
podryga [215]

Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Functions

  • Function Notation
  • Exponential Property [Rewrite]:                                                                   \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Property [Root Rewrite]:                                                           \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

We are given the following and are trying to find the second derivative at <em>x</em> = 2:

\displaystyle f(2) = 2

\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}

When we differentiate this, we must follow the Chain Rule:                             \displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big]

Use the Basic Power Rule:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} (2x + 6yy')

We know that y' is the notation for the 1st derivative. Substitute in the 1st derivative equation:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 6y(6\sqrt{x^2 + 3y^2}) \big]

Simplifying it, we have:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]

We can rewrite the 2nd derivative using exponential rules:

\displaystyle \frac{d^2y}{dx^2} = \frac{3\big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]}{\sqrt{x^2 + 3y^2}}

To evaluate the 2nd derivative at <em>x</em> = 2, simply substitute in <em>x</em> = 2 and the value f(2) = 2 into it:

\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = \frac{3\big[ 2(2) + 36(2)\sqrt{2^2 + 3(2)^2} \big]}{\sqrt{2^2 + 3(2)^2}}

When we evaluate this using order of operations, we should obtain our answer:

\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = 219

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0
2 years ago
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