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3 years ago

-. Is Electricity naturally produced in our environment.

1 answer:

5 0

Electricity is not a naturally occurring energy phenomenon like oil from the ground, but it must be created and refined at electrical power plants using other energy sources. The natural resources that create electric energy are usually non-renewable, with some exceptions.

Hope this helps

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Explain why 5.00 grams of salt does not contain the same number of particles as 5.0 grams of sugar

Tom [10]

Answer:

5.00 grams of salt contain more particles than 5.0 grams of sugar

Explanation:

Salt = NaCl

Molar mass = 58.45 g/mol

Sugar = C₁₂H₂₂O₁₁

Molar mass = 342.3 g/mol

Sugar's molar mass is higher than salt.

So 1 mol of sugar weighs more than 1 mol of salt

But 5 grams of salt occupies more mole than 5 grams of sugar

5 grams of salt = 5g / 58.45 g/m = 0.085 moles

5 grams of sugar = 5g/ 342.3 g/m = 0.014 moles

In conclusion, we have more moles of salt in 5 grams; therefore there are more particles than in 5 g of sugar.

3 0

3 years ago

How to atoms form a new substance

marin [14]

Answer:

they join together

Explanation:

6 0

3 years ago

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A sealed 1.0L flask is filled with 0.500 mols of I_2 and 0.500 mols of Br_2. When the container achieves equilibrium the equilib

DochEvi [55]

Answer:

[IBr] = 0.049 M.

Explanation:

Hello there!

In this case, according to the balanced chemical reaction:

$I_2+Br_2\rightarrow 2IBr$

It is possible to set up the following equilibrium expression:

$K=\frac{[IBr]^2}{[I_2][Br_2]} =0.0110$

Whereas the the initial concentrations of both iodine and bromine are 0.50 M; and in terms of $x$ (reaction extent) would be:

$0.0110=\frac{(2x)^2}{(0.50-x)^2}$

Which can be solved for $x$ to obtain two possible results:

$x_1=-0.0277M\\\\x_2=0.0245M$

Whereas the correct result is 0.0245 M since negative results does not make any sense. Thus, the concentration of the product turns out:

$[IBr]=2x=2*0.0249M=0.049M$

Regards!

7 0

3 years ago

Function of starch solution

serious [3.7K]

Answer:

Starch is a viable indicator in the titration process because it turns deep dark blue when iodine is present in a solution. When starch is heated in water, decomposition occurs and beta-amylose is produced

5 0

3 years ago

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7. The equilibrium constant Kc for the reaction H2(g) + I2(g) ⇌ 2 HI(g) is 54.3 at 430°C. At the start of the reaction there are

Juli2301 [7.4K]

Answer:

[H2] = 0.0692 M

[I2] = 0.182 M

[HI] = 0.826 M

Explanation:

Step 1: Data given

Kc = 54.3 at 430 °C

Number of moles hydrogen = 0.714 moles

Number of moles iodine = 0.984 moles

Number of moles HI = 0.886 moles

Volume = 2.40 L

Step 2: The balanced equation

H2 + I2 → 2HI

Step 3: Calculate Q

If we know Q, we know in what direction the reaction will go

Q = [HI]² / [I2][H2]

Q= [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Q =(n(HI)²) /(nH2 *nI2)

Q = 0.886²/(0.714*0.984)

Q =1.117

Q<Kc This means the reaction goes to the right (side of products)

Step 2: Calculate moles at equilibrium

For 1 mol H2 we need 1 mol I2 to produce 2 moles of HI

Moles H2 = 0.714 - X

Moles I2 = 0.984 -X

Moles HI = 0.886 + 2X

Step 3: Define Kc

Kc = [HI]² / [I2][H2]

Kc = [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Kc =(n(HI)²) /(nH2 *nI2)

KC = 54.3 = (0.886+2X)² /((0.714 - X)*(0.984 -X))

X = 0.548

Step 4: Calculate concentrations at the equilibrium

[H2] = (0.714-0.548) / 2.40 = 0.0692 M

[I2] = (0.984 - 0.548) / 2.40 = 0.182 M

[HI] = (0.886+2*0.548) /2.40 = 0.826 M

6 0

3 years ago

Read 2 more answers