Here is the process I did:
2(6x+4)-6+2x=3(4x+3)+1
Step 1: Distribute the 2 to the numbers in the parentheses (6x +4) on the left side of the equation
6x(2)+4(2)-6+2x=3(4x+3)+1
12x+8-6+2x=3(4x+3)+1
Step 2: On the left side of the equation combine like terms
x's go with x's (12x and 2x):
(12x + 2x)+8-6=3(4x+3)+1
14x+8-6=3(4x+3)+1
normal numbers go with normal numbers ( 8 and -6):
14x+(8+(-6))=3(4x+3)+1
14x+2=3(4x+3)+1
Step 3: Distribute the 3 to the numbers in the parentheses (4x+3) on the right side of the equation
14x+2=4x(3) +3(3) + 1
14x+2=12x + 9 + 1
Step 4: On the right side of the equation combine like terms
normal numbers go with normal numbers ( 9 and 1):
14x+2=12x + (9 + 1)
14x+2=12x + 10
Step 5: Bring 2 from the left side to the right by subtracting it to both sides
14x+(2-2)=12x + (10-2)
14x = 12x + 8
Step 6: Bring 12x from the right side to the left by subtracting it to both sides
(14x - 12x) = (12x - 12x) + 8
2x = 8
Step 7: Isolate x by dividing 2 to both sides
x = 4
Hope this helped!