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PolarNik [594]
3 years ago
13

I NEED YOUR HELPP !!!

Mathematics
2 answers:
Paladinen [302]3 years ago
6 0

Answer:7 4ts

Step-by-step explanation:

ira [324]3 years ago
3 0

Answer:

y = -\frac{1}{2} x - 4

Step-by-step explanation:

1. The slope-intercept form of any linear equation is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = slope.

2. First, to find the slope, we can use the two points from the given line which are (-10,1) and (2,-5). Afterward, we plug in those values to this formula: \frac{y_2-y_1}{x_2-x_1}

  • \frac{-5-1}{2-(-10)}
  • \frac{-6}{12}
  • -\frac{1}{2}

3. Now that we have our slope, our equation will look like this so far: y = -\frac{1}{2} x + b

4. Since we're aware that b is the y-intercept, b = -4 because the line intersects the y-axis at (0,-4).

5. Now that we have the values of b and m, our equation will build up to this: y = -\frac{1}{2} x - 4

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Find the nth degree polynomial function with real coefficients satisfying the given conditions.
RUDIKE [14]
\bf (x+1)(x-3)(x-2-4i)(x-2+4i)
\\\\
\textit{now, let's take a peek at }(x-2-4i)(x-2+4i)\\
\textit{and recall our }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
(x-2-4i)(x-2+4i)\implies [(x-2)-(4i)][(x-2)+(4i)]
\\\\\
[(x-2)^2-(4i)^2]\implies [(x^2-2x+4)-(4^2\boxed{i^2})]
\\\\\
[(x^2-2x+4)-(16\cdot \boxed{-1})]\implies [(x^2-2x+4)+16]
\\\\
(x^2-2x+20)\\\\
-----------------------------

\bf thus
\\\\

\begin{array}{llll}
(x+1)(x-3)\\(x-2-4i)(x-2+4i)
\end{array}\implies (x+1)(x-3)(x^2-2x+20)
\\\\\\
(x^2-2x-3)(x^2-2x+20)\implies 
\begin{array}{llll}
x^4-2x^3+20x^2-2x^3\\+4x^2-40x+3x^2-6x+60
\end{array}
\\\\\\
x^4-4x^3+27x^2-46x+60
4 0
3 years ago
What is the height of a cone with radius 5 and volume=100 π?
timurjin [86]
The height of the cone would be 10 being that fact that if multiplied by 2 you get 20x 5 equals 100
3 0
3 years ago
Read 2 more answers
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