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4 years ago

13

For each day that Sasha travels to work, the probability that she will experience a delay due to traffic is 0.2. Each day can be

considered independent of the other days. For the next 21 days that Sasha travels to work, what is the probability that Sasha will experience a delay due to traffic on at least 3 of the days?

1 answer:

lions [1.4K]4 years ago

6 0

Answer:

0.8213

Step-by-step explanation:

-This is a binomial probability problem given by the function:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}$

Given that n=21 and p=0.2, the probability that she experience a delay on at least 3 days is calculated as:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 3)=1-P(X$

Hence, the probability that she experience delay on at least 3 days is 0.8213

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