Answer:
Step-by-step explanation: see attachment below
, and 
. Subtracting this from the numerator gives a remainder of
, and 
. Subtracting this from the previous remainder gives a new remainder of
is not a multiple of 
, so we're done. Then
Answer:
Step-by-step explanation:
In this particular case we have the following system of equations:
y
=
−
3
x
+
4
[
E
q
.
1
]
x
+
4
y
=
−
6
[
E
q
.
2
]
Substituting
[
E
q
.
1
]
in
[
E
q
.
2
]
:
x
+
4
(
−
3
x
+
4
)
=
−
6
Applying the distributive property on the left side:
x
−
12
x
+
16
=
−
6
Simplifying
:
−
11
x
=
−
22
Solving for
y
:
x
=
−
22
−
11
=
2
Substituting
x
=
2
in
[
E
q
.
1
]
:
y
=
−
3
(
2
)
+
4
=
−
2
Therefore
, the solutions are
x
=
2
and
y
=
−
2
Answer:
7
Step-by-step explanation:
https://www.numerade.com/questions/reasoning-in-exercises-35-and-36-you-are-melting-a-rectangular-block-of-wax-to-make-candles-how-ma-2/
This link lets you access a video for the correct answer
Answer:
Step-by-step explanation:
y=-1/2(x+10)^2+14
2y=-(x+10)^2+28
(x+10)^2=28-2y
L.H.S. is positive.
so 28-2y≥0
28≥2y
or 2y≤28
or y≤ 14
Range is (-∞,14]
