What would you use to solve the equation 12.7 = j-3.4

2 answers:

4 0

By the Addition Principle of Equality, I would add 3.4 to both sides of the equation to get rid of the constant term -3.4 on the right-hand side.

12.7 + 3.4 = j - 3.4 + 3.4
16.1 = j

So, j is equal to 16.1.

MrRissso [65]3 years ago

4 0

12.7 = j - 3.4

We're simply just trying to get j by itself.

So, add 3.4 to both sides.

12.7 + 3.4 = j

Simplify.

16.1 = j

So, j = 15.1

~Hope I helped!~

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Mikey has $100 to spend on books. She wants to buy at least 14 books. Hardback books cost $15.00 and paperback books cost $7.00.

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8 0

3 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers: