3 years ago

What’s the critical points for this question?

Mathematics

1 answer:

V125BC [204]3 years ago

6 0

The critical point is (0,316)(-6,-116)

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3w = -27 (equation)

kotykmax [81]

W=-9

Explanation: 3w=-27

Divide 3 from -27

-27 divided by 3 = -9

5 0

3 years ago

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yarga [219]

Answer:

$(x-5)^2+(y-2)^2=9\\$

Step-by-step explanation:

So, you basically want the equation of the circle.

Given:

Center(C): $C(5, 2)$

$r=3$

The equation of circle is:

$(x-h)^2+(y-k)^2=r^2\\$

Where, $(h, k)$ represents the center point and $r$ is the radius of the circle.

Plotting the values in the equation:

$(x-5)^2+(y-2)^2=3^2\\$

$(x-5)^2+(y-2)^2=9\\$

This is the equation of the circle of center (5, 2) and radius 3.

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3 years ago

What is the y intercept of y= -3x

tatuchka [14]

Answer:

(0,0)

Step-by-step explanation:

y= -3x

The y intercept is the y value when x =0

Let x =0

y = -3(0)

y = 0

(0,0)

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3 years ago

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What is the value of x in the equation 1.5(x + 4) - 3=4.5(x-2)

anyanavicka [17]

Hi there!

The Eqn. is :-

1.5 (x + 4) - 3 = 4.5 (x - 2)

1.5x + 6 - 3 = 4.5x - 9

Combining the like terms :-

1.5x - 4.5x = - 9 - 6 + 3

- 3x = - 15 + 3

- 3x = - 12

x = $\dfrac {- 12}{- 3}$

x = 4

Hence, the required answer is → x = 4

~ Hope it helps!

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3 years ago

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For each triangle, find the missing side length to the nearest tenth. :

Lana71 [14]

We can use trigonometry. The cosine of 15 will be the side adjacent to the 15-degree side (the one we are looking for) divided by 20, the hypotenuse. As cos(15) is about .966, we get 19.32 as the side we are looking for.

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