Answer:
B. 2
Step-by-step explanation:
1.87
11 x 17 / 100 = 1.87
Part A.
Ashwin had a 4-cm cube.
volume of cube = side^3
volume = (4 cm)^3 = 64 cm^3
Ashwin has 64 small cubes.
We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.
A. v = 2 * 4 * 7 = 28
B. v = 4 * 5 * 6 = 120
C. v = 5 * 5 * 4 = 100
D. v = 4 * 7 * 5 = 140
E. v = 3 * 5 * 4 = 60
Part A. answer: A, E
Part B.
Dora had a 5-cm cube.
volume of cube = side^3
volume = (5 cm)^3 = 125 cm^3
Dora has 125 small cubes.
We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.
A. v = 3 * 3 * 8 = 72
B. v = 3 * 4 * 5 = 60
C. v = 6 * 6 * 4 = 144
D. v = 5 * 8 * 4 = 160
E. v = 3 * 5 * 4 = 60
Part B. answer: A, B, E
I assume you meant to write 5^c = 125. The equivalent logarithmic expression for this would be ㏒₅125=c.
Answer:
a) alternate interior angles theorem
b) OXP ≅ XOL
c) XO ≅ OX
d) reflexive property (i'm not sure about this one)
e) ΔXOP ≅ ΔOXL
f) cpctc
make sure to double check the fourth one
It is 50 thousands because 5 times 10 = 50.
