2 years ago

Enter a number into the blank to make the equation true.

Mathematics

2 answers:

yKpoI14uk [10]2 years ago

8 0

Answer:

779

Step-by-step explanation:

Allushta [10]2 years ago

5 0

Where is the equation?

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Natalka [10]

C - Irrational D- irrational E- Addition

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3 years ago

What is the equation 2y=x-8 In y intercept form?

Artyom0805 [142]

The answer would be y=x-4

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3 years ago

Si el área de una figura rectangular esta dada por A-bxh,¿cual es la siguiente expresiones representa el área de la puerta

stealth61 [152]

Respuesta:

3x² + 5x - 2

Explicación paso a paso:

Dado que :

Área del rectángulo, A = largo * ancho

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Área = (3x - 1) * (x + 2)

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2 years ago

If a triangle with angle measures 40,30.and 120 centimeters possible?

vagabundo [1.1K]

No, the longest side must be less than the sum of the smaller sides or else they won't connect (try it yourself with straw or something)

40+30>120
70>120
false, therfor they canonot be a triangle

7 0

3 years ago

Read 2 more answers

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

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3 years ago