\begin{gathered}\{\begin{array}{ccc}3x+5y=2&|\cdot(-3)\\9x+11y=14\end{array}\\\underline{+\{\begin{array}{ccc}-9x-15y=-6\\9x+11y=14\end{array}}\ \ |\text{add both sides of equations}\\.\ \ \ \ \ -4y=8\ \ \ |:(=4)\\.\ \ \ \ \ y=-2\\\\\text{substitute the value of y to the first equation}\\\\3x+5\cdot(-2)=2\\3x-10=2\ \ \ |+10\\3x=12\ \ \ |:3\\x=4\\\\Answer:\ x=4;\ y=-2\to(4;\ -2)\end{gathered}
{
3x+5y=2
9x+11y=14
∣⋅(−3)
−9x−15y=−6
9x+11y=14
add both sides of equations
. −4y=8 ∣:(=4)
. y=−2
substitute the value of y to the first equation
3x+5⋅(−2)=2
3x−10=2 ∣+10
3x=12 ∣:3
x=4
Answer: x=4; y=−2→(4; −2)
Complete question :
The Venn diagram relating to the question can be found in the picture attached below :
Answer:
A.) 15 ; b.) 17 ; c.) 20 ; d.) 19 ; e.) 55 ; 67; 76 ;100 ; F.) 369
Step-by-step explanation:
Let :
Cars = C ; Motorcycle = M ; Tricycle = T ; Walking = W
a) How many students ride in a tricycle, motorcycle and car going to their school
Intersection of the 3 modes;
(C n M n T) = 15 ; it is the number which sits in between all the three circles.
B.) How many students ride in both a motorcycle and a tricycle?
(M n T) = 17 ; number in the middle of both circles representing motorcycle and tricycle
C.) How many students ride in both a motorcycle and a car?
(M n C) = 20 ; number in the middle of both circles representing motorcycle and Car
D) How many students ride in both a car and tricycle?
(C n T) = 19 ; number in the middle of both circles representing Car and tricycle
e.)How many students go to school
in a car only = 55
in a motorcycle only = 67
Tricycle only = 76
Walking = 100
F.) How many Grade Seven students of Koronadal National Comprehensive High School are there in all?
(100 + 67 + 76 + 55 + 19 + 20 + 17 + 15) = 369
Answer:
the answer is B.FALSE
Step-by-step explanation:
hope it helps
Answer:
Less than. <
Step-by-step explanation:
Here is your answer
The angle opposite of the larger side is greater and vice versa.
Here
smallest side= AC (8cm)< BC (9cm) <AB (10cm)
So,
angles opposite to these sides are
B <A <C
HOPE IT IS USEFUL