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3 years ago

If a, b, and c are prime numbers, do (a + b.and c have a common factor that is greater than 1 ?

1 answer:

8 0

Let's do the math. In the example a =2, b = 3, c = 5. If we are trying to see if the sum of these numbers has a common factor more than 1 do the math. 2 + 3 + 5 = 10. Ten has four factors which are 1, 2, 5, and 10. So the answer to your question is yes.

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Solve this system using substitution then write your answer as an ordered pair (x,y) X-5y=4 and Y=2x+14

Nikolay [14]

Answer:

(74/9,274/9)

Step-by-step explanation:

You have

x-5y=4 and

y=2x+14

so we subsitute y in the first equation

x-5(2x+14)=4

x-10x-70=4

-9x=74

x=74/9

so y=2(74/9)+14

y=148/9+14

y=274/9

so the oredered pair is

(74/9,274/9)

4 0

3 years ago

A study of high school students in a college preparatory curriculum was designed to measure the effect of time spent doing homew

sammy [17]

C. grades in courses because it depends on how much the students study to get their grades

6 0

3 years ago

Find the probability that the person is frequently or occasionally involved in charity work.

Schach [20]

Given the table below which shows the result of a survey that asked 2,881 people whether they are involved in any type of charity work.

$\begin{tabular}
{|c|c|c|c|c|c|}
 &Frequently&Occassionally&Not at all&Total\\[1ex]
Male&227&454&798&1,479\\
Female &205&450&747&1,402\\
Total&432&904&1,545&2,881
\end{tabular}$

Part A:

If a person is chosen at random, the probability that the person is frequently or occassinally involved in charity work is given by

$P(being \ frequently \ involved \ or \ being \ occassionally \ involved)\\ \\= \frac{432}{2881} + \frac{904}{2881} = \frac{1336}{2881}=\bold{0.464}$

Part B:

If a person is chosen at random, the probability that the person is female or not involved in charity work at all is given by

$P(being
 \ female \ or \ not \ being \ involved)\\ \\= 
\frac{1402}{2881} + \frac{1545}{2881}-\frac{747}{2881} = 
\frac{2200}{2881}=\bold{0.764}$

Part C:

If a person is chosen at random, the probability that the person is male or frequently involved in charity work is given by

$P(being
 \ male \ or \ being \ frequently \ involved)\\ \\= 
\frac{1479}{2881} + \frac{432}{2881}-\frac{227}{2881} = 
\frac{1684}{2881}=\bold{0.585}$

Part D:

If a person is chosen at random, the probability that the person is female or not frequently involved in charity work is given by

$P(being
 \ female \ or \ not \ being \ frequently \ involved)\\ \\= 
\frac{1402}{2881} + \frac{904}{2881} + \frac{1545}{2881}-\frac{450}{2881}-\frac{747}{2881} = 
\frac{2654}{2881}=\bold{0.921}$

Part E:

The events "being female" and "being frequently involved in charity work" are not mutually exclusive because being a female does not prevent a person from being frequently involved in charity work.

Indeed from the table, there are 205 females who are frequently involved in charity work.

Therefore, the answer to the question is "No, because 205 females are frequently involved charity work".

4 0

3 years ago

Find the radius of the button

nika2105 [10]

Shush fhoncizbizxoabcobad

5 0

3 years ago

Need answer now !!

Law Incorporation [45]

Answer:

Yes

Step-by-step explanation:

Each value only maps out to one value, so that means it is a function.

7 0

3 years ago

Read 2 more answers