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2 years ago

What's 7/8 as a decimal? a. 7.8 b. .875 c. 8.7 d. .78

1 answer:

OverLord2011 [107]2 years ago

5 0

If you would like to write 7/8 as a decimal, you can do this using the following steps:

7/8 = (125*7)/1000 = 875/1000 = 0.875 = .875

The correct result would be b. .875.

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Two roller coasters are vying for the title of the steepest drop the first ride has a hill that drops 140 feet in a 40 foot run

muminat

Answer:

They have the same slope

Step-by-step explanation:

Given

Coaster 1:

$Drops = 140ft$

$Run = 40ft$

Coaster 2:

$Drops = 105ft$

$Run = 30ft$

First, we calculate the slope (m) of both coasters

$m = \frac{Rise}{Run}$

$m = \frac{Drops}{Run}$

For coaster 1:

$m = \frac{140ft}{40ft}$

$m = \frac{140}{40}$

$m = 3.5$

For coaster 1:

$m = \frac{105ft}{30ft}$

$m = \frac{105}{30}$

$m = 3.5$

$m = m=>3.5 = 3.5$

By comparison, they have the same slope

8 0

2 years ago

UnansweredIf Measure of angle a is 155°, what is Measure of angle c?

Gnom [1K]

Answer: 155°

because ∠a and ∠c are 2 opposing angles => m∠a = m∠c = 155°

Step-by-step explanation:

8 0

2 years ago

A bag of skittles contains green and purple candies in the ratio of 3 green to 4 purple. If there are 24 purple candies in the b

Basile [38]

Answer:

Their would be 12 green skittles.

6 0

2 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

2 years ago

a rectangle has a length of (x +6) feet and width of (x-2) feet. has a area of 48 feet squared, find the dimensions

Shalnov [3]

(x^2)+4x-12=48

I Hope this is what you were looking for. If it isn't this just plug it in

x=6

4 0

2 years ago