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2 years ago

5

PLEASE HELP ME AND HURRY TOO NO LIBKS PLEASE I WILL GIVE BRAINLIEST

1 answer:

arsen [322]2 years ago

8 0

First one is denominator, then opposite of denominator.. i would wait for someone else to answer. but i’m pretty sure that’s correct. sorry if it is incorrect.. good luck on the rest of your assessment!!

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Evaluate the composition of functions.

valina [46]

Answer:

2

Step-by-step explanation:

Fill in each function's argument and do the arithmetic.

$h(g(f(\sqrt{10})))=h(g(2(\sqrt{10})^2-7))=h(g(2\cdot 10-7))=h(g(13))\\\\=h(\dfrac{4-13}{9})=h(\dfrac{-9}{9})=h(-1)\\\\=\sqrt{-(-1)+3}=\sqrt{4}=\boxed{2}$

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2 years ago

A number was multiplied by 6 then increased by 3 and the result was 33

Nina [5.8K]

The number that you are trying to find is 5

3 0

3 years ago

HELP PLZZZZ! thank you

Setler79 [48]

1. Same length.

2.vertically opposite angle.

3.BAC =BDE

4.AC = DE

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3 0

2 years ago

What is the value of sin(t) if cos(t)=0.1, and t is in quadrant 1

Marizza181 [45]

Answer:

$sin(t)=\frac{\sqrt{99}}{10}$

Step-by-step explanation:

Remember that

If angle t belong to the First Quadrant

then

The value of sin(t) and cos(t) are positive values

we know that

$sin^2(t)+cos^2(t)=1$ ---> by trigonometric identity

we have

$cos(t)=0.1=\frac{1}{10}$

substitute

$sin^2(t)+(\frac{1}{10})^2=1$

$sin^2(t)+\frac{1}{100}=1$

$sin^2(t)=1-\frac{1}{100}$

$sin^2(t)=\frac{99}{100}$

$sin(t)=\frac{\sqrt{99}}{10}$

8 0

3 years ago

Can someone help :))

katovenus [111]

Answer:

the first one, and the last one

Step-by-step explanation:

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2 years ago