Answer:
A. The risk of type l error increases and becomes too high.
Step-by-step explanation:
The overall level of significance increases as the number of t- tests ( used for comparing two, three or four means separately ) increases. This in turn increases the risk of type I error.
We might be tempted to apply the two sample t- test to all possible pairwise comparisons of means. This type of running t- test to several means comparison has the risk of increasing overall level of significance
Answer:
1/3,1/4,and so on like increasing in number
Find the next two terms in the given sequence, then write it in recursive form. A.) {7,12,17,22,27,...} B.) { 3,7,15,31,63,...}
iren [92.7K]
Answer:
A) a_n = 5n + 2
B) a_n = (2^(n + 1)) - 1
Step-by-step explanation:
A) The sequence is given as;
{7,12,17,22,27,...}
The differences are:
5,5,5,5.
This is an arithmetic sequence following the formula;
a_n = a_1 + (n - 1)d
d is 5
Thus;
a_n = a_1 + (n - 1)5
Now, a_1 = 7. Thus;
a_n = 7 + 5n - 5
a_n = 5n + 2
B) The sequence is given as;
{ 3,7,15,31,63,...}
Now, let's write out the differences of this sequence:
Differences are:
4, 8, 16, 32
This shows that it is a geometric sequence with a common ratio of 2.
In the given sequence, a_1 = 3 and a_2 = 7 and a_3 = 15
Thus, a_2 = 2a_1 + 1
Also, a_(2 + 1) = 2a_2 + 1
Combining both equations, we can deduce that: a_(n + 1) = 2a_n + 1
Thus; a_n can be expressed as:
a_n = (2^(n + 1)) - 1
Answer:
the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds
Step-by-step explanation:
The computation of the number of seconds that you and your friend would be have the similar distance from the starting line is shown below:
As we know that
Speed = Distance ÷ Time
SO,
Time = Distance ÷ speed
= 10 meters ÷ difference in speed
= 10 meters ÷ (6 meters per second - 5.5 meters per second)
= 10 meters ÷ 0.5 meters per second
= 20 seconds
hence, the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds
