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4 years ago

Write an equation of the line y-intercept =-11/2

Mathematics

1 answer:

Vadim26 [7]4 years ago

5 0

To write an equation of a line, you need to also know the slope or have a graph

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228 divided by 12 equals???

vlabodo [156]

228/12 = 19. To check, turn it into multiplication, by doing 19 * 12, which equals 228.

Hope this helps! ☺♥

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3 years ago

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Estimate 49% of 162. Use mental math to calculate 49% of 162. ???

svet-max [94.6K]

$if\ 50\%\ of\ 162\ is\ 81\ so\ 49\%\ of\ 162\ is\ about\ 79-80$

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3 years ago

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Name the property the equation illustrates.<br> (ab)3 = a (63)<br> Accociative Property of addition

Delvig [45]

<h3><u>Question:</u></h3>

Name the property the equation illustrates

(ab)3 = a(b3)

A. Commutative property of addition

B. Associative property of Multiplication

C. Associative Property of Addition

D. Inverse Property of Multiplication

<h3><u>Answer:</u></h3>

Associative property of Multiplication

<h3><u>Solution:</u></h3>

From given equation

(ab)3 = a(b3)

We have to find the property used here

We find the brackets are interchanged

So here, given is a multiplication equation

Therefore, Associative property of Multiplication is used

<h3><u>Associative property of Multiplication:</u></h3>

This property says that when we are multiplying it does not matter where you put the parenthesis

The result will be same wherever we put the parenthesis in multiplying two or more numbers

Which means,

$a \times (b \times c) = (a \times b) \times c$

Therefore, from given,

$a \times (b \times 3) = (a \times b) \times 3$

Thus associative property of multiplication is used

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4 years ago

Please help with math 30 points

Nookie1986 [14]

Y=7 and x=7. hope thi helps

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4 years ago

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During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th

ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given : J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901 (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

$P(X=x)^nC_xp^x(1-p)^{n-x}$

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901 (from (1))

The probability that he makes at least 13 of them will be :-

$P(x\geq13)=P(x=13)+P(x=14)$

$=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898$

∴ The required probability = 0.5898

5 0

3 years ago