Concept:
Frequency- It is defined as the number of oscillations occur in one second.
Its SI unit is Hertz (Hz)
Given: Produced sound vibrations is 18,500 cycles in 0.75 seconds
∵ In 0.75 second, produced sound has oscillations = 18,500 cycles
∴ In 1.0 second, produced sound has oscillations = (18,500 ÷ 0.75) Hz
The frequency of the sound will be ≈ 24,667 Hz
From the study of the given graph, only the animals (c) Cats, (b) Moths and (a) Bats can hear the produced sound because their upper audible frequency range is greater than 24,667 Hz.
Answer:
A.
Explanation:
When the light travels through the lenses and disperses it can create other colors around objects that aren't there.
Answer:
R = 73.25 m
Explanation:
We have,
Initial speed of the ball is 27 m/s
It is projected at an angle of 40 degrees
The maximum range of the ball is given by :

Plugging all the values we get :

So, the maximum range of the ball is 73.25 m
42.5g
Explanation:
Given parameters:
Mass of N₂= 35g
Unknown:
Mass of NH₃ = ?
Solution:
Equation of the reaction:
N₂ + 3H₂ → 2NH₃
To solve this problem, we work from the known species to the unknown. The known here is the reacting mass of the N₂. From this we can find the number of moles of the N₂.
Number of moles of N₂ = 
molar mass of N₂ = 28g/mol
Number of moles =
= 1.25moles
From the equation of the reaction:
1 mole of N₂ produced 2 moles of NH₃
1.25 moles of N₂ will produce 2 x 1.25 = 2.5moles of NH₃
Mass of NH₃ = Number of moles of NH₃ x molar mass of NH₃
= 2.5 x (14 + 3)
= 42.5g
Learn more:
number of moles brainly.com/question/1841136
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Induced motion or movement