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Daniel [21]
3 years ago
5

Three resistors of resistances, R1=10Ω, R2=5Ω, R3=20Ω are connected in a circuit in such way that same amount of current flows t

hrough them. Draw a circuit diagram showing the correct connections of the three resistors, a cell of 2.5V, an ammeter and a voltmeter across R3. Calculate the potential difference across R3.
Physics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer

Explanation:

As the three resistors are connected in series, the expression to be used for the  

calculation of RT equivalent resistance

is:  

RT = R1 + R2 + R3

We replace the data of the statement in the previous expression and it remains:  

5 10 15 RT + R1 + R2 + R3 + +

We perform the mathematical operations that lead us to the result we are looking for:  

RT - 30Ω

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We know that a ship, even though it is madeup of tonnes of iron, floats on water. How do you feel about the scientists who found
slamgirl [31]
I feel admiration and respect for them, and I feel grateful and humble.
3 0
3 years ago
A proton has a speed of 3.50 Ã 105 m/s when at a point where the potential is +100 V. Later, itâs at a point where the potential
ruslelena [56]

Answer:

(a). The change in the protons electric potential is 0.639 kV.

(b). The change in the potential energy of the proton is 1.022\times10^{-16}\ J

(c). The work done on the proton is -8\times10^{-18}\ J.

Explanation:

Given that,

Speed v= 3.50\times10^{5}\ m/s

Initial potential V=100 V

Final potential = 150 V

(a). We need to calculate the change in the protons electric potential

Potential energy of the proton is

U=qV=eV

Using conservation of energy

K_{i}+U_{i}=K_{f}+U_{f}

\dfrac{1}{2}mv_{i}^2+eV_{i}=\dfrac{1}{2}mv_{f}^2+eV_{f}

]\dfrac{1}{2}mv_{i}^2-]\dfrac{1}{2}mv_{f}^2=e(V_{f}-V_{i})

\dfrac{1}{2}mv_{i}^2-]\dfrac{1}{2}mv_{f}^2=e\Delta V

\Delta V=\dfrac{m(v_{i}^2-v_{f}^2)}{2e}

Put the value into the formula

\Delta V=\dfrac{1.67\times10^{-27}(3.50\times10^{5}-0)^2}{2\times1.6\times10^{-19}}

\Delta V=639.2=0.639\ kV

(b). We need to calculate the change in the potential energy of the proton

Using formula of potential energy

\Delta U=q\Delta V

Put the value into the formula

\Delta U=1.6\times10^{-19}\times639.2

\Delta U=1.022\times10^{-16}\ J

(c). We need to calculate the work done on the proton

Using formula of work done

\Delta U=-W

W=q(V_{2}-V_{1})

W=-1.6\times10^{-19}(150-100)

W=-8\times10^{-18}\ J

Hence, (a). The change in the protons electric potential is 0.639 kV.

(b). The change in the potential energy of the proton is 1.022\times10^{-16}\ J

(c). The work done on the proton is -8\times10^{-18}\ J.

5 0
3 years ago
A clothes dryer in a home draws a current of 10 amps when connected on a special 220-volts household circuit.what is the resista
aliya0001 [1]

Answer:

22Ω

Explanation:

if    V ⇒ voltage

      I ⇒ current

      R ⇒ resistance

V = IR

220 = 10 x R

220 / 10 = R

22 = R

8 0
2 years ago
How much energy is used when a 110kw appliance is used for 3 hours
Bogdan [553]
We could take the easy way out and just say

(110 kW) x (3 hours) = 330 kilowatt hours .

But that's cheap, and hardly worth even 5 points.
If we want to talk energy, let's use the actual scientific unit of energy.
________________________________________________

" 110 kw " means 110,000 watts = 110,000 joules/second .

(3 hours) x (3600 sec/hour) = 10,800 seconds.

(110,000 joules/second) x (10,800 seconds) = 1.188 x 10⁹ Joules

 That's

==>  1,188,000,000 joules

==>  1,188,000 kilojoules

==>  1,188 megajoules

==>  1.188 gigajoules

Atsa nawfulotta energy ! 
It goes back to that "110 kw appliance" that we started with. 
That's no common ordinary household appliance.  110 kw is something like
147 horsepower.  In order to bring 110 kw into your house, you'd need to
take 458 Amperes through the 240-volt line from the pole.  Most houses
are limited to 100 or 200 Amperes, tops.  And the TRANSFORMER on
the pole, that supplies the whole neighborhood, is probably a 50 kw unit.  
6 0
3 years ago
Example of optical object​
Alik [6]

Answer:

Telescope,cameras

Hope it helped

5 0
3 years ago
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