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sattari [20]
3 years ago
7

A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 22 m/

s at an angle θ = 23 ° below horizontal. The stone moves without air resistance; use a Cartesian coordinate system with the origin at the stone's initial position.

Physics
1 answer:
Alina [70]3 years ago
5 0

Answer:

V = 25.3 , θf = 36.7° below the horizontal

Explanation:

Given Vo = 22m/s , θ = 23°

Vx = VoCosθ

Vy = VoSinθ – gt

t = total time of flight

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A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal
Dmitry [639]
The resultant force on the animal = Resultant mass * total acceleration 
F = 0.2 * 2.5 to the right
F = 0.5 to the right.

As, girl exerting a force of 3.5 N & it's not mentioned that she is in right or left, so the force exerting by boy would be either:
3.5-0.5 = 3  OR  3.5+0.5 = 4

If boy exerting a greater force then, answer will be 4 N & if girl exerting a greater force the, answer will be 3 N

Hope this helps!
3 0
3 years ago
Read 2 more answers
(15 points) :^|
mihalych1998 [28]
That is FALSE. The equation to calculate the charges has a distance component that is in the denominator which means that it is inversely proportional (as the distance os greater the force is smaller)
7 0
3 years ago
A force did 80 j of work on an object in 4 m how big was the force
yanalaym [24]

Work = (force) x (distance)

80 J = (force) x (4 m)

Force = (80 J) / (4 m)  =  20 N

That's IF the force was in the same direction as the 4m of motion.
If the force was kind of slanted, then it had to be stronger, and
it had a component of 20N in the direction of the motion.

3 0
3 years ago
Suppose the coefficient of static friction between the road and the tires on a car is 0.638 and the car has no negative lift. Wh
larisa [96]

Answer:

12.6332454263 m/s

Explanation:

m = Mass of car

v = Velocity of the car

\mu = Coefficient of static friction = 0.638

g = Acceleration due to gravity = 9.81 m/s²

r = Radius of turn = 25.5 m

When the car is on the verge of sliding we have the force equation

\dfrac{mv^2}{r}=\mu mg\\\Rightarrow v=\sqrt{\mu gr}\\\Rightarrow v=\sqrt{0.638\times 9.81\times 25.5}\\\Rightarrow v=12.6332454263\ m/s

The speed of the car that will put it on the verge of sliding is 12.6332454263 m/s

4 0
3 years ago
Your high-fidelity amplifier has one output for a speaker of resistance 8 Ω. How can you arrange two 8-Ω speakers, one 4-Ω speak
ANTONII [103]

Answer:

(a) 8Ω (b)  Ratio = Parra/P8 ohm = 1

Explanation:

Solution

Recall that,

An high-fidelity amplifier has one output for a speaker of resistance of = 8 Ω

Now,

(a) How can  two 8-Ω speakers be  arranged, when one =  4-Ω speaker, and one =12-Ω speaker

The Upper arm is : 8 ohm, 8 ohm

The Lower arm is : 12 ohm, 4 ohm

The Requirement is  = (16 x 16)/(16 + 16) = 8 ohm

(b) compare  your arrangement  power output of with the power output of a single 8-Ω speaker

The Ratio = Parra/P8 ohm = 1

8 0
3 years ago
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