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Lisa [10]
3 years ago
12

True or False. If your skin is wet, the body's resistance to electric shocks increases.

Physics
2 answers:
Svetllana [295]3 years ago
4 0

Answer:

Pretty sure its false, water increases electric shock

Explanation:

Tpy6a [65]3 years ago
4 0

Answer: False

Explanation:

It would never increase because you are already wet, and you can not get any wetter.

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A spring on a horizontal surface can be stretched and held 0.2 m from its equilibrium position with a force of 16 N. a. How much
nekit [7.7K]

Answer:

a   W_{3.5} = 490 \  J

b  W_{2.5} =  250 \  J

Explanation:

Generally the force constant is mathematically represented as

       k  = \frac{F}{x}

substituting values given in the question

=>   k  = \frac{16}{0.2}

=>   k  =  80 \ N /m

Generally the workdone  in stretching the spring 3.5 m is mathematically represented as

       W_{3.5} =  \frac{1}{2}  *  k  *  (3.5)^2

=>     W_{3.5} =  \frac{1}{2}  *  80  *  (3.5)^2

=>    W_{3.5} = 490 \  J

Generally the workdone  in compressing the spring 2.5 m is mathematically represented as

        W_{2.5} =  \frac{1}{2}  *  k  *  (2.5)^2

=>      W_{2.5} =  \frac{1}{2}  *  80 *  (2.5)^2

=>       W_{2.5} =  250 \  J

5 0
3 years ago
What is the average speed of a boy who jogs 250 meters in 110 seconds
Ede4ka [16]

2.27 mps repeating.

This is the last question ill ever answer here. Thanks for being the last.

8 0
3 years ago
Read 2 more answers
The gravitational potential energy of the ball changes as it bounces. Where is the ball located when its gravitational potential
Cloud [144]

When the planet is closest to the Sun, speed v and kinetic energy are the highest, and gravitational potential energy is the lowest. When the planet moves farther away, the speed and kinetic energy decrease, and the gravitational potential energy increases.

5 0
3 years ago
A thallium source with a half-life of 3.7 years was certified at 10 kBq 10 years ago. What is its activity now?
Murrr4er [49]

Answer:

the activity of thallium is 1.54 kBq .

Explanation:

given,

half life = 3.7 years

R₀ = 10  kBq                    

time = 10 years                    

R = R_0\times e^(\dfrac{-0.693}{t_{1/2}}\times t)

R = 10\times e^(\dfrac{-0.693}{3.7}\times 10)

R = 10 × (0.153667)                      

R = 1.5367 ≈ 1.54 kBq                

hence, the activity of thallium is 1.54 kBq .

7 0
4 years ago
On a distance vs. time graph, how do you know when the object is moving away from its starting position?
Ainat [17]
U know by if they are in first place
8 0
3 years ago
Read 2 more answers
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