This polynomial will be 3 with the leading coefficient of 1
153000 x 0.124 = 18972 employees with some college experience
153000 x 0.841 = 128673 employees with bachelor degree
128673 - 18972 = 109701 more writers and authors with bachelor's degree than just some college experience
Answer:
x= 6
Step-by-step explanation:

You will subtract 10x from 12x and get 2x

Subtract 4 from 16 to get 12

You will then divide both sides by 2
= 
x= 6
The second one is hard to read but since ∠3 is 54° you should just start from there
Hope this helps
Answer:
t = [0.493,4.2]
Step-by-step explanation:
The height of the rocket straight up into the air is given by :

We need to find the interval the rocket be at least 43 feet above the ground.

So, the required interval during which the rocket is at least 43 feet above the ground is [0.493,4.2].
Given:
Two endpoints of a diameter of a circle:
P (-7, -10)
Q (3, 2)
a) To find the center of the circle, find the midpoint of the two points:
midpoint:
(x2 - x1 )/ 2 , (y2 - y1) / 2
x= (2 - (-7))/2 = 4.5
y= (3 - (-10))/2 = 6.5
Therefore, the center of the circle is at C(4.5, 6.5)
b) To find the radius of the circle, we need to find the distance between the two points and divide by 2.
d = √(y2-y1)^2 + (x2 - x1)^2
d = √(2-(-7))^2 + (3 - (-10))^2
d = 5√10 = diameter
r = d/2 = 5√10 /2