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murzikaleks [220]

3 years ago

13

What is the answer for this question please

2 answers:

diamong [38]3 years ago

7 0

Answer:

2.7

Step-by-step explanation:

den301095 [7]3 years ago

6 0

Answer: 2.7

Step-by-step explanation:

Each line represents 0.2, so between 2.6 and 2.8 is 2.7

You might be interested in

Simplify <br> (3k^4) (7k^5)

Hunter-Best [27]

Answer:

21 k^9

Step-by-step explanation:

(3k^4) (7k^5)

Multiply the coefficients

3*7 = 21

Add the exponents

k^(4+5) = k^(9)

Put back together

21 k^9

4 0

3 years ago

mr.browns salary is 32,000 and imcreases by $300 each year, write a sequence showing the salary for the first five years when wi

chubhunter [2.5K]

Hello!

We have the following data:

a1 (first term or first year salary) = 32000

r (ratio or annual increase) = 300

n (number of terms or each year worked)

We apply the data in the Formula of the General Term of an Arithmetic Progression, to find in sequence the salary increases until it exceeds 34700, let us see:

formula:

$a_n = a_1 + (n-1)*r$

* second year salary

$a_2 = a_1 + (2-1)*300$

$a_2 = 32000 + 1*300$

$a_2 = 32000 + 300$

$\boxed{a_2 = 32300}$

* third year salary

$a_3 = a_1 + (3-1)*300$

$a_3 = 32000 + 2*300$

$a_3 = 32000 + 600$

$\boxed{a_3 = 32600}$

* fourth year salary

$a_4 = a_1 + (4-1)*300$

$a_4 = 32000 + 3*300$

$a_4 = 32000 + 900$

$\boxed{a_4 = 32900}$

* fifth year salary

$a_5 = a_1 + (5-1)*300$

$a_5 = 32000 + 4*300$

$a_5 = 32000 + 1200$

$\boxed{a_5 = 33200}$

We note that after the first five years, Mr. Browns' salary has not yet surpassed 34700, let's see when he will exceed the value:

* sixth year salary

$a_6 = a_1 + (6-1)*300$

$a_6 = 32000 + 5*300$

$a_6 = 32000 + 1500$

$\boxed{a_6 = 33500}$

* seventh year salary

$a_7 = a_1 + (7-1)*300$

$a_7 = 32000 + 6*300$

$a_7 = 32000 + 1800$

$\boxed{a_7 = 33800}$

* eighth year salary

$a_8 = a_1 + (8-1)*300$

$a_8 = 32000 + 7*300$

$a_8 = 32000 + 2100$

$\boxed{a_8 = 34100}$

* ninth year salary

$a_9 = a_1 + (9-1)*300$

$a_9 = 32000 + 8*300$

$a_9 = 32000 + 2400$

$\boxed{a_9 = 34400}$

* tenth year salary

$a_{10} = a_1 + (10-1)*300$

$a_{10} = 32000 + 9*300$

$a_{10} = 32000 + 2700$

$\boxed{a_{10} = 34700}$

we note that in the tenth year of salary the value equals but has not yet exceeded the stipulated value, only in the eleventh year will such value be surpassed, let us see:

* eleventh year salary

$a_{11} = a_1 + (11-1)*300$

$a_{11} = 32000 + 10*300$

$a_{11} = 32000 + 3000$

$\boxed{\boxed{a_{11} = 35000}}\end{array}}\qquad\checkmark$

Respuesta:

In the eleventh year of salary he will earn more than 34700, in the case, this value will be 35000

________________________

¡Espero haberte ayudado, saludos... DexteR! =)

7 0

3 years ago

Moose plans to eat 8 of his mom's minty

antoniya [11.8K]

Answer:

75%

Step-by-step explanation:

$\frac{6}{8} \times 100\% = 75\%$

6 0

2 years ago

If you punched 1 raffle ticket, what is the probability of winning of only 10 tickets are winners and 179 total tickets were sol

Licemer1 [7]

Answer:

1 out of 179

Step-by-step explanation:

8 0

3 years ago

A pieces of wire was 12.36 centimeters long. Thelma cut the wire into 6 pieces of equal length. What was the length of each piec

Zigmanuir [339]

Answer:

2.06cm

Step-by-step explanation:

Given data

Length of wire= 12.36cm

We are told that it was cut into 6 pieces

Hence, the length of a piece is

=12.36/6

=2.06cm

Therefore, the answer is 2.06cm

3 0

3 years ago