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Dmitrij [34]
3 years ago
14

Can someone please help

Mathematics
1 answer:
Masja [62]3 years ago
5 0

Answer:

3 or c

Step-by-step explanation:

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A metalworker has a metal alloy that is 15​% copper and another alloy that is 75​% copper. How many kilograms of each alloy shou
lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

<em><u>Solution:</u></em>

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

<em><u>Solve the equation for "x"</u></em>

15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0
3 years ago
Factor this trinomial completely . -10x^2+36x^2+16x
klasskru [66]
26x^2+16x


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3 years ago
PLS HELP!!!!!
gladu [14]
\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\left(\dfrac{7}{4}\right)^{11}=\dfrac{7^{11}}{4^{11}}\to D)
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3 years ago
Given the equation -2x+3y=12, find the missing value in the ordered pair 3, <br><br> Noo linkss plz
astraxan [27]

Answer:

(3,6)

Step-by-step explanation:

-2x+3y=12

Let x = 3

-2(3) +3y = 12

-6+3y = 12

Add 6 to each side

-6+6 +3y = 12+6

3y = 18

Divide each side by 3

3y/3 = 18/3

y = 6

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3 years ago
From net earnings of $740 per month for the rent on an apartment she says the two friends what percent of income is her rent pay
Gwar [14]
<span>$200 / $740 *100% = 27%

</span>
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3 years ago
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