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Dmitrij [34]
3 years ago
14

Can someone please help

Mathematics
1 answer:
Masja [62]3 years ago
5 0

Answer:

3 or c

Step-by-step explanation:

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Can you show a better photo some of the question is cut off
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3 years ago
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Write these expressions in exponential form:
Crazy boy [7]

1. 10^5

2. z^5*x^3*y^2

3. 1

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3 years ago
The weight of water is 62 1/2 per cubic feet. Water that weighs 325 lbs will fill how many cubic feet
yulyashka [42]

Water that weighs 325 lbs will fill 5.2 cubic feet.

Step-by-step explanation:

This is a simple question of cross multiplication

<u>DATA:</u>

<em>1. The weight of water for 1 cubic feet is 62.5</em>

<em>2. The weight of water for 'X' cubic feet is 325 </em>

<em>3. To find x, form an equation:</em>

Cubic feet : Weight of water

     1           :         62.5

     X           :         325

<em>4. Cross multiply</em>

X x 62.5 = 1 x 325

62.5X = 325

<em>5. Make X the subject</em>

X = \frac{325}{62.5}

<em>6. Solve to find X</em>

X = 5.2 cubic feet

Therefore, water that weighs 325 lbs will fill 5.2 cubic feet.

Key words: Conversion

Learn more about conversions at

  • brainly.com/question/1548911
  • brainly.com/question/555814
  • brainly.com/question/4837736

#LearnwithBrainly

4 0
4 years ago
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng
gladu [14]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

\green{Now:- } \\  \green{ \: Area  \: Under \:  Unshaded \:  Part }

Total Area - Area Under Unshaded Part

Area= 2\pi -  \frac{2\pi}{3}  \\ Area =  \frac{6\pi - 2\pi}{3}   \\ Area =  \frac{4\pi}{3}  \:  \: ans

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

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3 years ago
What is the simplified form of 2(15-3)x(15-3)divided by 2?
Darya [45]
PEMDAS
2(12)x(12)/2
24x12/2
288/2
144
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