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3 years ago

Can someone please help

Mathematics

1 answer:

Masja [62]3 years ago

5 0

Answer:

3 or c

Step-by-step explanation:

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Someone please help?

Digiron [165]

The answer to your question is,

$3.84, you take $69.20 and divide it by 18 and there is your answer!

-Mabel <3

4 0

3 years ago

Natalia solved the problem 74.4/12=6.2. complete the model with partial products check Natalia's work using multiplication

tia_tia [17]

Answer:

Natalia's work is wrong.

Step-by-step explanation:

Natalia divided a decimal number by an entire number. Since division is a operation derived from multiplication, the best approach to check if work was good is multiplying the given result by denomination, that is:

1) $x = 6.2\times 12$ Given.

2) $x = \left(6+0.2\right)\times 12$ Definition of addition.

3) $x = 6\times 12 + 0.2\times 12$ Distributive property.

4) $x = 72 + \frac{2}{10}\times 12$ Definitions of multiplication and decimal number.

5) $x = 72 +[2\cdot (10)^{-1}]\cdot 12$ Definition of division/Associative property.

6) $x = 72 + [2\cdot 12]\cdot (10)^{-1}$ Associative property.

7) $x = 72 + 24\cdot 10^{-1}$ Definition of multiplication.

8) $x = 72 + \frac{24}{10}$ Definition of divsion.

9) $x = 72 + 2.4$ Defintion of decimal number.

10) $x = 74.4$ Definition of addition/Result

Natalia's work is wrong.

5 0

2 years ago

If f(x) = 3x + 2 and g(x) = 2x – 2, what is (f – g)(x)?

DiKsa [7]

I hope this helps you

4 0

3 years ago

There are 9 apples.there are 6 fewer apples than oranges.how oranges are there

serious [3.7K]

Answer:

Step-by-step explanation

Either your 5, your just trying brain.ly out, or your trolling don't care either way

8 0

2 years ago

When will the equation p(b)=520(0.88)^b have a value less than 100?

yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × $0.88^{b}$ to have a value less than 100 we can establish inequality as:

p(b) < 100

or, 520 × $0.88^{b}$ < 100

or, $\frac{520}{520}$ × $0.88^{b}$ < $\frac{100}{520}$

or, $0.88^{b}$ < $\frac{1}{5.2}$

or, ㏒ ( $0.88^{b}$ ) < ㏒ ( $\frac{1}{5.2}$ )

or, b× ㏒ 0.88 < ㏒ ( $\frac{1}{5.2}$ )

or, $\frac{log (\frac{1}{5.2}) }{log (0.88)}$ < b

or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

3 0

3 years ago