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Naddik [55]
3 years ago
14

are the graphs of the lines in the pair parallel? explain. y equals two thirds x minus 17. 4 x minus 6 y equals negative 6. a. n

o, since the slopes are different. b. no, since the y-intercepts are different. c. yes, since the slopes are the same and the y-intercepts are different. d. yes, since the slopes are the same and the y-intercepts are the same
Mathematics
1 answer:
nasty-shy [4]3 years ago
6 0
The slope of the line is the quotient when the negative of the numerical coefficient of x is divided by the numerical coefficient of y. The slope of the first line is 2/3 and that of the second line is -4/-6 or 2/3. Thus, the answer is letter C. 
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almond37 [142]

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

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Answer:

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Step-by-step explanation:

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trapecia [35]

Answer:

See explanation

Step-by-step explanation:

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so the origin does not belong to the needed part. Shade the part, which does not include origin.

3. Find the common region of these two shaded parts - this is the solution to the system of two inequalities.

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