Answer:
g = 
Step-by-step explanation:
Given
2(g - h) = b + 4 ← distribute parenthesis on left side
2g - 2h = b + 4 ( add 2h to both sides )
2g = b + 4 + 2h ( divide both sides by 2 )
g = 
Answer:
1/0.4=10/4=5/2...............
Answer:
the answer of the question is k = 176
Answer:
6.18% of the class has an exam score of A- or higher.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What percentage of the class has an exam score of A- or higher (defined as at least 90)?
This is 1 subtracted by the pvalue of Z when X = 90. So



has a pvalue of 0.9382
1 - 0.9382 = 0.0618
6.18% of the class has an exam score of A- or higher.