Find the interquartile range of the following data set.
2 answers:
Answer:
Step-by-step explanation:
The data set given is:
57,63,44,29,36,62,48,50,42,34
Arrange in ascending order:
29,34,36,42,44,48,50,57,62,63
Place parenthesis around the number making two equal sets.
(29,34,36,42,44) | (48,50,57,62,63)
↑ ↑
Q1 Q3
Q1 = 36 , Q3 = 57
So, IQR = Q3-Q1
IQR = 57-36
IQR = 21
Answer:
Step-by-step explanation:
The data set is given,
Arrange the data set in ascending order.
Split the data set into two equal sets.
Find the median of the lower half and upper half.
Interquartile range = median of upper half - median of lower half
The interquartile range for the number of points scored at ten basketball games is 21.
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Answer:
The equation for the inequality is , c + d = 200
And , $ 2.50 c + $ 1.25 d = $ 100
Step-by-step explanation:
Given as :
The total quantity of cider and donuts for charity = 200
The price of donuts holes =$ 1.25
The price of cider = $ 2.50
The total price money for the cider and donuts = $ 100
Let the quantity of each donuts = d
And The quantity of cider = c
Now, According to question
The total quantity of cider and donuts for charity = 200
Or, The quantity of cider + the quantity of each donuts = 200
Or, c + d = 200 ..........A
And , $ 2.50 c + $ 1.25 d = $ 100 ............B
So, Solving equations
2.50 × ( c + d ) = 2.50 × 200
I.e 2.50 c + 2.50 d = 500
And 2.50 c + 1.25 d = 100
Or, ( 2.50 c + 2.50 d ) - ( 2.50 c + 1.25 d ) = 500 - 100
Or, (2.50 c - 2.50 c ) + ( 2.50 d - 1.25 d ) = 400
Or, 0 + 1.25 d = 400
∴ d =
I.e d = 320
The quantity of donuts = 320
Hence The equation for the inequality is , c + d = 200
And , $ 2.50 c + $ 1.25 d = $ 100 Answer