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3 years ago

12

Find the interquartile range of the following data set.

2 answers:

sasho [114]3 years ago

8 0

Answer:

$\huge\boxed{IQR = 21}$

Step-by-step explanation:

The data set given is:

57,63,44,29,36,62,48,50,42,34

Arrange in ascending order:

29,34,36,42,44,48,50,57,62,63

Place parenthesis around the number making two equal sets.

(29,34,36,42,44) | (48,50,57,62,63)

↑ ↑

Q1 Q3

Q1 = 36 , Q3 = 57

So, IQR = Q3-Q1

IQR = 57-36

IQR = 21

sweet [91]3 years ago

7 0

Answer:

$\huge \boxed{\sf A. \ 21}$

Step-by-step explanation:

The data set is given,

$\sf 57 \ 63 \ 44 \ 29 \ 36 \ 62 \ 48 \ 50 \ 42 \ 34$

Arrange the data set in ascending order.

$\sf 29 \ 34 \ 36 \ 42 \ 44 \ 48 \ 50 \ 57 \ 62 \ 63$

Split the data set into two equal sets.

$\sf 29 \ 34 \ 36 \ 42 \ 44 \ \ \ 48 \ 50 \ 57 \ 62 \ 63$

Find the median of the lower half and upper half.

$\sf Median \ of \ lower \ half = 36$

$\sf Median \ of \ upper \ half = 57$

Interquartile range = median of upper half - median of lower half

$\sf IQR = 57 - 36$

$\sf IQR = 21$

The interquartile range for the number of points scored at ten basketball games is 21.

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3 years ago

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Yuri [45]

Answer:

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Distribution would be an increase to find 80% salt.

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3 years ago

Read 2 more answers

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borishaifa [10]

Equation to find number's value: $\frac{1}{5}n + 3n = 2n + 42$

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Equation: $\frac{1}{5}n + 3n = 2n + 42$

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